Bunuel wrote:
Train X leaves New York at 1 A.M. and travels east at a speed of x miles per hour. If train Z leaves New York at 2 A.M. and travels east, at what rate of speed will train Z have to travel in order to catch train X at exactly 5:30 A.M.?
(A) 5x/6
(B) 9x/8
(C) 6x/5
(D) 9x/7
(E) 3x/2
This question can be approached with the "close the gap in a chase" method, and by choosing numbers.
Train A, when traveling alone, creates the distance between A and B. That's the gap.
When Train B starts moving, the chase is on.
Time = 3.5 hours
B chases A, closes the gap, only while both move.
B closes the gap at a relative speed, r, of (B's rate - A's rate). What is r? rt = D, so...
The gap will close at D/t = r.
To find r, pick an easy "gap" distance: 70 mi (because t = 3.5)
A travels for 1hr, A's rate = 70 mph = x
The distance/gap of 70 mi is closed by relative speed of (B-A)
Relative speed? D/t = r
70/3.5 = 20
The difference between A's speed and B's speed is 20 mph.
B is chasing; B travels at 20 mph faster than A
B's speed: (70 + 20) = 90 mph
With x = 70, check choices until the answer is 90.
(A) 5x/6 = 350/6 = 5_. No
(B) 9x/8 = 6300/8 = 7_. No
(C) 6x/5 = 4200/5 = 8_. No
(D) 9x/7 = 6300/7= 90. MATCH
(E) 3x/2 = 210/2 = 105. No
Answer D