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Kit can finish 3/4 of a job in 2 hours and Nita can finish 3/4 of a jo [#permalink]
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Solution



Given:

    • We are given that Kit can do ¾ of a job in 2hours.
    • Nita can complete ¾ of the same job in 4 hours.
To find:

    • We need to find the extra time that Nita will spend if Kit and Nita both work separately to complete 4x work.

Approach and Working:

Kit finishes ¾ of a job in 2 hours.
    • ¾ of the wok in 2 hours.
    • So, Kit will complete the work in 8/3 hours.
    • Hence, Kit will take 4x*8/3= 32x/3 day to complete 4x job.

Now, Nita can finish 3/4 of a job in 3 hours.
    • ¾ of the wok in 3 hours.
    • So, Nita will complete the work in 12/3=4 hours.
    • Hence, Kit will take 4*4= 16 days to complete 4x job.

Hence, Nita spends 16-32/3= 16/3 days more than Kit to complete the work.

Hence, option B is the correct answer.
Answer: B
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Kit can finish 3/4 of a job in 2 hours and Nita can finish 3/4 of a jo [#permalink]
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Quote:
Kit can finish 3/4 of a job in 2 hours and Nita can finish 3/4 of a job in 3 hours. How much more time will Nita spend on 4x jobs than Kit will?


A. 8x/3

B. 16x/3

C. 8x

D. 32x/3

E. 16x


Let the larger task = 4x jobs and the smaller task = \(\frac{3}{4}\) of a job.
For the smaller task, the time difference for Nita and Kim = 3-2 = 1 hour.

\(\frac{(larger-task)}{(smaller-task)}\) = \(4x/\frac{3}{4}\) = \(\frac{16x}{3}\).

Since the larger task is \(\frac{16x}{3}\) times the smaller task, the time difference for the larger task must be \(\frac{16x}{3}\) times the time difference for the smaller task:
\(\frac{16x}{3} * 1 = \frac{16x}{3}\) hours.


Originally posted by GMATGuruNY on 20 Jun 2018, 07:22.
Last edited by GMATGuruNY on 21 Jun 2018, 06:38, edited 4 times in total.
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Kit can finish 3/4 of a job in 2 hours and Nita can finish 3/4 of a jo [#permalink]
GMATGuruNY wrote:
In the problem as posted, the value of \(x\) seems unnecessary and misused.
I believe that the following reflects the intent of the problem:

Quote:
Kit can finish 3/4 of a job in 2 hours and Nita can finish 3/4 of a job in 3 hours. How many more hours will Nita spend on 4 jobs than Kit will?

A. 8/3

B. 16/3

C. 8

D. 32/3

E. 16

For \(\frac{3}{4}\) of a job, the time difference for Nita and Kim = 3-2 = 1 hour.

\(\frac{(larger-job)}{(smaller-job)}\) = \(4/\frac{3}{4}\) = \(\frac{16}{3}\).

Since the larger job is 16/3 times the smaller job, the time difference for the larger job must be 16/3 times the time difference for the smaller job:
16/3 * 1 = 16/3 hours.



Hi GMATGuruNY

How did you get? What does lager/smaller job mean?
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Kit can finish 3/4 of a job in 2 hours and Nita can finish 3/4 of a jo [#permalink]
Expert Reply
Mo2men wrote:

How did you get? What does larger/smaller job mean?


Please revisit my solution, in which I've clarified the reasoning, as follows:
Larger task = 4x jobs.
Smaller task = \(\frac{3}{4}\) of a job.
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Re: Kit can finish 3/4 of a job in 2 hours and Nita can finish 3/4 of a jo [#permalink]
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Bunuel wrote:
Kit can finish 3/4 of a job in 2 hours and Nita can finish 3/4 of a job in 3 hours. How much more time will Nita spend on 4x jobs than Kit will?


A. 8x/3

B. 16x/3

C. 8x

D. 32x/3

E. 16x


The rate of Kit is (3/4)/2 = 3/8.

The rate of Nita is (3/4)/3 = 3/12 = 1/4.

It will take Kit 4x/(3/8) = 32x/3 hours to complete 4x jobs.

It will take Nita 4x/(1/4) = 16x hours to complete the job. Thus, the difference of their two times is:

16x - 32x/3 = 48x/3 -32x/3 = 16x/3

Answer: B
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Re: Kit can finish 3/4 of a job in 2 hours and Nita can finish 3/4 of a jo [#permalink]
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Re: Kit can finish 3/4 of a job in 2 hours and Nita can finish 3/4 of a jo [#permalink]
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