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A survey is done in am office among 120 people to know how many of the

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a70
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A survey is done in am office among 120 people to know how many of the [#permalink] New post   Updated on: 14 Aug 2018, 04:15
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A survey is done in am office among 120 people to know how many of them like their boss. 50 people not only like their boss but also admire him. If an employee is selected at random, is the probability that he neither likes his boss nor admires him less than 20%?
1. 10 employees do not like their boss
2. 80% of the employees admire their boss
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A

Originally posted by a70 on 31 Jul 2018, 00:58.
Last edited by a70 on 14 Aug 2018, 04:15, edited 1 time in total.
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chetan2u
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A survey is done in am office among 120 people to know how many of the [#permalink] New post   31 Jul 2018, 01:14
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ankit2601 wrote:
A survey is done in am office among 120 people to know how many of them like their boss. 50 people not only like their boss but also admire him. If an employee is selected at random, is the probability that he neither likes his boss nor admires him less than 20%?
1. 10 employees do not like their boss
2. 80% of the employees admire their boss


SO 4 groups -
1) Only Like boss - L
2) Only admire boss - A
3) both - B
4) neither - N

L+A+B+N=120
B=50

IS N< 20% 0r 20*120/100 that is ' Is N < 24?"

1. 10 employees do not like their boss
so A+N=10 therefore \(\leq{10}\)
ans YES
suff

2. 80% of the employees admire their boss
so remaining 20 5 can be all who do not like also, that is L is sub set of A, then N=20%....NO
if even any one of remaining likes then N<20%.. YES
insuff

A
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Raksat
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Re: A survey is done in am office among 120 people to know how many of the [#permalink] New post   09 Aug 2018, 08:53
chetan2u wrote:
ankit2601 wrote:
A survey is done in am office among 120 people to know how many of them like their boss. 50 people not only like their boss but also admire him. If an employee is selected at random, is the probability that he neither likes his boss nor admires him less than 20%?
1. 10 employees do not like their boss
2. 80% of the employees admire their boss


SO 4 groups -
1) Only Like boss - L
2) Only admire boss - A
3) both - B
4) neither - N

L+A+B+N=120
B=50

IS N< 20% 0r 20*120/100 that is ' Is N < 24?"

1. 10 employees do not like their boss
so B+N=10 therefore \(\leq{10}\)
ans NO
suff

2. 80% of the employees admire their boss
so remaining 20 5 can be all who do not like also, that is L is sub set of A, then N=20%....YES
if even any one of remaining likes then N<20%
insuff

A

Sir,
i couldn't understand how it could be B+N =10, IMO it should be A+N =10
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chetan2u
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Re: A survey is done in am office among 120 people to know how many of the [#permalink] New post   09 Aug 2018, 09:31
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Raksat wrote:
chetan2u wrote:
ankit2601 wrote:
A survey is done in am office among 120 people to know how many of them like their boss. 50 people not only like their boss but also admire him. If an employee is selected at random, is the probability that he neither likes his boss nor admires him less than 20%?
1. 10 employees do not like their boss
2. 80% of the employees admire their boss


SO 4 groups -
1) Only Like boss - L
2) Only admire boss - A
3) both - B
4) neither - N

L+A+B+N=120
B=50

IS N< 20% 0r 20*120/100 that is ' Is N < 24?"

1. 10 employees do not like their boss
so B+N=10 therefore \(\leq{10}\)
ans NO
suff

2. 80% of the employees admire their boss
so remaining 20 5 can be all who do not like also, that is L is sub set of A, then N=20%....YES
if even any one of remaining likes then N<20%
insuff

A

Sir,
i couldn't understand how it could be B+N =10, IMO it should be A+N =10


Thanks it was a typing error. Edited
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Rw27
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Re: A survey is done in am office among 120 people to know how many of the [#permalink] New post   26 Aug 2018, 11:49
Hi Chetan

Can you please explain the answer again. How have you used the 'not like' scenario to derive the answer.
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A survey is done in am office among 120 people to know how many of the [#permalink] New post   29 Aug 2018, 07:18
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chetan2u wrote:
ankit2601 wrote:
A survey is done in am office among 120 people to know how many of them like their boss. 50 people not only like their boss but also admire him. If an employee is selected at random, is the probability that he neither likes his boss nor admires him less than 20%?
1. 10 employees do not like their boss
2. 80% of the employees admire their boss


SO 4 groups -
1) Only Like boss - L
2) Only admire boss - A
3) both - B
4) neither - N

L+A+B+N=120
B=50

IS N< 20% 0r 20*120/100 that is ' Is N < 24?"

1. 10 employees do not like their boss
so A+N=10 therefore \(\leq{10}\)
ans NO
suff

2. 80% of the employees admire their boss
so remaining 20 5 can be all who do not like also, that is L is sub set of A, then N=20%....YES
if even any one of remaining likes then N<20%
insuff

A


Shldnt the answer be yes, the probability is less than 20% instead of No as written.
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cancerian
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Re: A survey is done in am office among 120 people to know how many of the [#permalink] New post   21 Nov 2018, 11:32
Hi guys , one query : can’t we do it like : probability of neither liking nor admiring =1- (50C1/120C1) as 50 people not only like but also admire the boss

Please suggest

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Re: A survey is done in am office among 120 people to know how many of the [#permalink] New post   16 Feb 2023, 09:19
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Re: A survey is done in am office among 120 people to know how many of the [#permalink]
16 Feb 2023, 09:19
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