How many flowers offered in the temple?

Note : all temples received equal flowers

lets start with the 4th temple , lets say all x flowers were given, then before dip x/2 flowers must have been left after offering in the 3rd temple. ( only then x/2 flowers could be doubled to become x and all offered in the 4th temple with nothing left over )

so x/2 flowers were left after offering made in the 3rd temple

going backwards .....
(x/2) left after 3rd temple + x given in the 3rd temple =(3x/2) {after dip, total flowers just before offering in the 3rd temple}
so before dip (3x/4)

(3x)/4 left after 2nd temple + x given in the 2nd temple = (7x)/4{after dip, total flowers just before offering in the 2nd temple}
so before dip (7x)/8

(7x)/8 left after 1st temple + x given in the 1st temple = (15x)/8{after dip, total flowers just before offering in the 1st temple}
so before dip (15x)/16

now since number of flowers have to be an integer then x has to be a multiple of 2,4,8 and 16
only 48 satisfies
Hence Answer = D