sandeepk123 wrote:
There are four temples, one plant of flower and a pond.
A boy goes there and before entering the first temple he plucks the flower and has to take a bath in the pond before entering into every temple.
The specialty of the pond is that if a person is carrying flowers with him and he takes a dip in the pond the number of the flowers gets doubled.
He takes a dip and offers some flowers in the first temple, then he again takes a dip and offers flowers in second temple , again the same in the third temple, and again the same in the fourth temple
The boy offers EQUAL number of flowers in all the four temples and goes back with EMPTY hand after offering flower in the fourth temple..How many flowers could he have offered in each temples?
A) 20
B) 24
C) 30
D) 48
E) 60
Note : all temples received equal flowers
lets start with the 4th temple , lets say all x flowers were given, then before dip x/2 flowers must have been left after offering in the 3rd temple. ( only then x/2 flowers could be doubled to become x and all offered in the 4th temple with nothing left over )
so x/2 flowers were left after offering made in the 3rd temple
going backwards .....
(x/2) left after 3rd temple + x given in the 3rd temple =(3x/2) {after dip, total flowers just before offering in the 3rd temple}
so before dip (3x/4)
(3x)/4 left after 2nd temple + x given in the 2nd temple = (7x)/4{after dip, total flowers just before offering in the 2nd temple}
so before dip (7x)/8
(7x)/8 left after 1st temple + x given in the 1st temple = (15x)/8{after dip, total flowers just before offering in the 1st temple}
so before dip (15x)/16
now since number of flowers have to be an integer then x has to be a multiple of 2,4,8 and 16
only 48 satisfies
Hence Answer = D