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Re: In the figure above, the measure of angle AOB is 120 degrees. If the [#permalink]
Bunuel wrote:

In the figure above, the measure of angle AOB is 120 degrees. If the radius of OB is x, then arc AB is what fraction of the area of sector AOB, in terms of x?


A π/x

B √3/x

C 2/x

D 3/x

E 4/x


Attachment:
2019-01-17_1517.png


Just a quick question, for this figure why are we not considering the outer sector with theta as \(240^o\)

making the answer as E.
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In the figure above, the measure of angle AOB is 120 degrees. If the [#permalink]
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Solution


Given:
    • Angle AOB = 120 degrees
    • Radius, OB = x

To find:
    • Length of arc, AB/area of sector AOB

Approach and Working:
    • Length of arc, AB = \(\frac{120}{360} * 2ᴨ * x = \frac{2ᴨx}{3}\)
    • Area of sector AOB = \(\frac{120}{360} * ᴨ * x^2 = \frac{ᴨx^2}{3}\)

Therefore, the answer is \(\frac{2ᴨx}{3}/\frac{ᴨx^2}{3} = \frac{2}{x}\)

Hence, the correct answer is Option C

Answer: C

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Re: In the figure above, the measure of angle AOB is 120 degrees. If the [#permalink]
Bunuel wrote:

In the figure above, the measure of angle AOB is 120 degrees. If the radius of OB is x, then arc AB is what fraction of the area of sector AOB, in terms of x?


A π/x

B √3/x

C 2/x

D 3/x

E 4/x



Attachment:
2019-01-17_1517.png



area of sector : 120/360 * pi * x2 and arc AB is 120/360 * 2 * pi * x

ratio would give us
2/x IMO C
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Re: In the figure above, the measure of angle AOB is 120 degrees. If the [#permalink]
Expert Reply
Bunuel wrote:

In the figure above, the measure of angle AOB is 120 degrees. If the radius of OB is x, then arc AB is what fraction of the area of sector AOB, in terms of x?


A π/x

B √3/x

C 2/x

D 3/x

E 4/x


Attachment:
2019-01-17_1517.png


Since the radius is x, the area is πx^2, and since AB corresponds to a 120 degree angle, the area of sector AOB is 120/360 * πx^2 = 1/3 * πx^2 = (πx^2)/3.

Next we determine the circumference of the entire circle and the arclength of arc AB.

Circumference = 2xπ, so arc AB is 120/360 * 2xπ = 1/3 * 2xπ = 2xπ/3.

Finally arc AB is (2xπ/3)/(πx^2/3) = 6xπ/3πx^2 = 2/x of the area of sector AOB.

Answer: C
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Re: In the figure above, the measure of angle AOB is 120 degrees. If the [#permalink]
Bunuel wrote:

In the figure above, the measure of angle AOB is 120 degrees. If the radius of OB is x, then arc AB is what fraction of the area of sector AOB, in terms of x?


A π/x

B √3/x

C 2/x

D 3/x

E 4/x


If x is the radius that means \(2pi * x\) is the perimeter and \(x^2 pi\) is the area

ARC AB is \(\frac{1}{3} of the total perimeter\) and area of AOB is also \(\frac{1}{3}\) of the total area.

This means that perimeter : area = (2pi*x/3) : (x^2*pi/3) = \(\frac{2}{x}\)
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Re: In the figure above, the measure of angle AOB is 120 degrees. If the [#permalink]
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