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A diet contains 300 grams of a mixture of two foods, food X

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A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   Updated on: 30 Jul 2012, 08:11
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A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?

(A) 150
(B) 145
(C) 100
(D) 160
(E) 140
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E

Originally posted by ju_1 on 20 May 2003, 11:49.
Last edited by Bunuel on 30 Jul 2012, 08:11, edited 1 time in total.
Edited the question and added the OA.
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A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   30 Jul 2012, 08:13
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harshavmrg wrote:
ju_1 wrote:
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?
(A) 150
(B)145
(C) 100
(D) 160
(E) 140


x(10%) y(15%)
38%
23% 28%

the protein parts in the final mixture for X:Y::23:28

hence

23 X
----------- = --------------
(23+28) 300

23/51 = x/300

x = 23 * 300
------------
51

hence x is approximately equal to 139.8

hence the answer is E


Keep it simple:

    \(0.1x+0.15(300-x)=38\);

    \(0.1x+45-0.15x=38\);

    \(0.05x=7\);

    \(\frac{5}{100}x=7\);

    \(x=\frac{700}{5}\);

    \(x=140\) (exactly).

Answer: E.
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   13 Aug 2012, 00:41
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X contains 30 gms of protein (10% of 300 gms)
Y contains 45 gms of protein (15% of 300 gms)
Resultant mixture contains 38 gms of protien.

using scale method :

____8___________7___
30 38 45
w1 w2

therefore,
w1/w2 = 7/8

7x+8x=300 gms
=> x=20

so, w1 = 7x=7(20) = 140 gms
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[#permalink] New post   20 May 2003, 21:08
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1.... 10/100*X + 15/100*Y = 38 (protein)

2.... X + Y = 300 (Total Mix)

Solve for X = 140
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   30 Jul 2012, 07:52
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ju_1 wrote:
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?
(A) 150
(B)145
(C) 100
(D) 160
(E) 140


x(10%) y(15%)
38%
23% 28%

the protein parts in the final mixture for X:Y::23:28

hence

23 X
----------- = --------------
(23+28) 300

23/51 = x/300

x = 23 * 300
------------
51

hence x is approximately equal to 139.8

hence the answer is E
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   18 Apr 2014, 22:12
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X+Y = 300

0.1X + 0.15Y = 38

X=140
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   07 Aug 2016, 06:02
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start with some numbers.
if x = 100, then y=200
protien from x = 10 and from y = 30 . total protein = 40. greater.. hmm. it means y is somewhat more than it should be. this implies x > 100.
x= 150 , then y=150
protein from x = 15 and from y = 22.5 total = 37.5..lesser
so answer is between 100 and 150 . if we see there are two choices 140 and 145. which one it should be?
well after increasing x by 50 we notice that we reduced total protein from 40 to 37.5 means 2.5. We just need to reduce the protein by 2.

Let us try 140 with this, protein from x = 14 , protein from y = 16+8 = 24. total = 38. this works!
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   07 Aug 2016, 10:53
.10x+.15(300-x)=38
x=140 grams
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A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   07 Aug 2016, 13:25
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Take equal proportion to have an idea of ratio,150 each. X will give 15g, Y will give 22.5g which is closer to 38 (37.5)
A little thought on the options D& E will give us E as the answer


Sent from my iPhone using GMAT Club Forum mobile app
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   07 Aug 2016, 21:52
I am a little confused about the wording here.

The question says "a diet provides exactly 38 grams of protein daily..." is it referring to the same diet or some other diet which could be more or less than 300 grams?

I feel if it is referring to the same diet then it should mention "THE diet provides...", don't you think?


ju_1 wrote:
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?

(A) 150
(B) 145
(C) 100
(D) 160
(E) 140
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   25 Sep 2016, 06:46
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10/100 (x) + 15/100 (300-x) = 38

10/100 (x) + 45 - 15/100 (x) = 38

-5/100 (x) = -7 --> x= 140
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   22 Nov 2017, 05:43
Bunuel wrote:
harshavmrg wrote:
ju_1 wrote:
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?
(A) 150
(B)145
(C) 100
(D) 160
(E) 140


x(10%) y(15%)
38%
23% 28%

the protein parts in the final mixture for X:Y::23:28

hence

23 X
----------- = --------------
(23+28) 300

23/51 = x/300

x = 23 * 300
------------
51

hence x is approximately equal to 139.8

hence the answer is E


Keep it simple: \(0.1x+0.15(300-x)=38\) --> \(x=140\) (exactly).

Answer: E.


hi Bunuel
really very simple, man
:cool:
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   22 Nov 2017, 08:24
Let x, y be the weight of food X, food Y in the mixture, respectively.
We have: x+y = 300 and 0,1x + 015y = 38 => x = 140.
Hence, the answer is E.
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   22 Nov 2017, 13:19
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ju_1 wrote:
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?

(A) 150
(B) 145
(C) 100
(D) 160
(E) 140


We can let x = the amount of X and y = the amount of Y. Let’s create two equations:

x + y = 300

y = 300 - x

And

0.1x + 0.15y = 38

0.1x + 0.15(300 - x) = 38

0.1x + 45 - 0.15x = 38

7 = 0.05x

140 = x

Answer: E
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   28 Mar 2018, 12:16
Alligation:

X Y
10% of 300 =30(value in gms) 15% of 300=45 (value in gms)

Aavg= 38 gms

X or A1 or W1= 7 : Y or A2 or W2= 8

X/Y= 7/8
Hence X = 7/15 of total

To get the amount in gms 7/15 of 300= 140. Hence E is the answer
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   24 Apr 2019, 12:58
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bhavinshah5685 wrote:
X contains 30 gms of protein (10% of 300 gms)
Y contains 45 gms of protein (15% of 300 gms)
Resultant mixture contains 38 gms of protien.

using scale method :

____8___________7___
30 38 45
w1 w2

therefore,
w1/w2 = 7/8

7x+8x=300 gms
=> x=20

so, w1 = 7x=7(20) = 140 gms


Please help VeritasKarishma
is the method correct? because X contains 10% protein , 10 % of what ? isn't it 10% of X's contribution? but it is taken 10% of total volume 300 grams
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   25 Apr 2019, 06:04
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ju_1 wrote:
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?

(A) 150
(B) 145
(C) 100
(D) 160
(E) 140


Food X has 10% protein
Food Y has 15% protein

The mix has (38/300)*100 = (38/3)% protein (so this is the average protein)

wX/wY = (15 - 38/3) / (38/3 - 10) = 7/8

So food X and food Y are mixed in the ratio 7:8 in the 300 gms of mix.
Food X must be 140 gms and food Y must be 160 gms.

Answer (E)
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A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   25 Apr 2019, 07:15
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ju_1 wrote:
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?

(A) 150
(B) 145
(C) 100
(D) 160
(E) 140


For mixture problems we need to check the average in the resultant mixture, in this case we need to check average protein in the resultant mixture and that is 38/3 (38/300*100%).
Now we need to compare it with x: |38/3-10|=8/3 and with Y: |15-38/3|=7/3
x:Y= 7/3:8/3 or 7:8
Proportion of x in the final mixture is therefore =7/15*300 or 140 (Option E)

Please hit +1Kudos :please
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   20 Oct 2020, 12:28
0.1x + 0.15 (300 - x) = 38
x = 140

Or you can plug in numbers to check:

Start with E) x = 140, y must be 1.5. 160 * 1.5 = 240.

Answer is E.
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink] New post   02 Jan 2021, 15:44
VeritasKarishma wrote:
ju_1 wrote:
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?

(A) 150
(B) 145
(C) 100
(D) 160
(E) 140


Food X has 10% protein
Food Y has 15% protein


The mix has (38/300)*100 = (38/3)% protein (so this is the average protein)

wX/wY = (15 - 38/3) / (38/3 - 10) = 7/8

So food X and food Y are mixed in the ratio 7:8 in the 300 gms of mix.
Food X must be 140 gms and food Y must be 160 gms.

Answer (E)


I'm really sorry but I couldn't understand how (15 - 38/3) / (38/3 - 10) = 7/8

Because since 38/3=12,6
which means that (15 - 38/3) / (38/3 - 10) = 2,4/4,6

how can I arrive to the 7/8 ?

Thank you very much!
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink]
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