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# A diet contains 300 grams of a mixture of two foods, food X

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Intern
Joined: 07 May 2003
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A diet contains 300 grams of a mixture of two foods, food X [#permalink]

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20 May 2003, 10:49
2
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A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?

(A) 150
(B) 145
(C) 100
(D) 160
(E) 140
[Reveal] Spoiler: OA

Last edited by Bunuel on 30 Jul 2012, 07:11, edited 1 time in total.
Edited the question and added the OA.

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Manager
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20 May 2003, 20:08
1
KUDOS
1.... 10/100*X + 15/100*Y = 38 (protein)

2.... X + Y = 300 (Total Mix)

Solve for X = 140

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Manager
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink]

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30 Jul 2012, 06:52
ju_1 wrote:
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?
(A) 150
(B)145
(C) 100
(D) 160
(E) 140

x(10%) y(15%)
38%
23% 28%

the protein parts in the final mixture for X:Y::23:28

hence

23 X
----------- = --------------
(23+28) 300

23/51 = x/300

x = 23 * 300
------------
51

hence x is approximately equal to 139.8

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Harsha

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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink]

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30 Jul 2012, 07:13
6
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Expert's post
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This post was
BOOKMARKED
harshavmrg wrote:
ju_1 wrote:
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?
(A) 150
(B)145
(C) 100
(D) 160
(E) 140

x(10%) y(15%)
38%
23% 28%

the protein parts in the final mixture for X:Y::23:28

hence

23 X
----------- = --------------
(23+28) 300

23/51 = x/300

x = 23 * 300
------------
51

hence x is approximately equal to 139.8

Keep it simple: $$0.1x+0.15(300-x)=38$$ --> $$x=140$$ (exactly).

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Kudos [?]: 136066 [6], given: 12724

Manager
Joined: 25 Jun 2012
Posts: 67

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WE: General Management (Energy and Utilities)
Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink]

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12 Aug 2012, 23:41
1
KUDOS
X contains 30 gms of protein (10% of 300 gms)
Y contains 45 gms of protein (15% of 300 gms)
Resultant mixture contains 38 gms of protien.

using scale method :

____8___________7___
30 38 45
w1 w2

therefore,
w1/w2 = 7/8

7x+8x=300 gms
=> x=20

so, w1 = 7x=7(20) = 140 gms

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Director
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Concentration: General Management, General Management
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink]

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18 Apr 2014, 21:12
1
KUDOS
X+Y = 300

0.1X + 0.15Y = 38

X=140
_________________

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TGC!
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I Assisted You => KUDOS Please
_____________________________________________________________________________

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Manager
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink]

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07 Aug 2016, 05:02
if x = 100, then y=200
protien from x = 10 and from y = 30 . total protein = 40. greater.. hmm. it means y is somewhat more than it should be. this implies x > 100.
x= 150 , then y=150
protein from x = 15 and from y = 22.5 total = 37.5..lesser
so answer is between 100 and 150 . if we see there are two choices 140 and 145. which one it should be?
well after increasing x by 50 we notice that we reduced total protein from 40 to 37.5 means 2.5. We just need to reduce the protein by 2.

Let us try 140 with this, protein from x = 14 , protein from y = 16+8 = 24. total = 38. this works!

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Director
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink]

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07 Aug 2016, 09:53
.10x+.15(300-x)=38
x=140 grams

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A diet contains 300 grams of a mixture of two foods, food X [#permalink]

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07 Aug 2016, 12:25
1
KUDOS
Take equal proportion to have an idea of ratio,150 each. X will give 15g, Y will give 22.5g which is closer to 38 (37.5)
A little thought on the options D& E will give us E as the answer

Sent from my iPhone using GMAT Club Forum mobile app

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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink]

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07 Aug 2016, 20:52
I am a little confused about the wording here.

The question says "a diet provides exactly 38 grams of protein daily..." is it referring to the same diet or some other diet which could be more or less than 300 grams?

I feel if it is referring to the same diet then it should mention "THE diet provides...", don't you think?

ju_1 wrote:
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?

(A) 150
(B) 145
(C) 100
(D) 160
(E) 140

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Senior Manager
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink]

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25 Sep 2016, 05:46
10/100 (x) + 15/100 (300-x) = 38

10/100 (x) + 45 - 15/100 (x) = 38

-5/100 (x) = -7 --> x= 140

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Manager
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink]

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22 Nov 2017, 04:43
Bunuel wrote:
harshavmrg wrote:
ju_1 wrote:
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?
(A) 150
(B)145
(C) 100
(D) 160
(E) 140

x(10%) y(15%)
38%
23% 28%

the protein parts in the final mixture for X:Y::23:28

hence

23 X
----------- = --------------
(23+28) 300

23/51 = x/300

x = 23 * 300
------------
51

hence x is approximately equal to 139.8

Keep it simple: $$0.1x+0.15(300-x)=38$$ --> $$x=140$$ (exactly).

hi Bunuel
really very simple, man

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Intern
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink]

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22 Nov 2017, 07:24
Let x, y be the weight of food X, food Y in the mixture, respectively.
We have: x+y = 300 and 0,1x + 015y = 38 => x = 140.

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Target Test Prep Representative
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Re: A diet contains 300 grams of a mixture of two foods, food X [#permalink]

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22 Nov 2017, 12:19
ju_1 wrote:
A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?

(A) 150
(B) 145
(C) 100
(D) 160
(E) 140

We can let x = the amount of X and y = the amount of Y. Let’s create two equations:

x + y = 300

y = 300 - x

And

0.1x + 0.15y = 38

0.1x + 0.15(300 - x) = 38

0.1x + 45 - 0.15x = 38

7 = 0.05x

140 = x

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Re: A diet contains 300 grams of a mixture of two foods, food X   [#permalink] 22 Nov 2017, 12:19
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