TheNightKing wrote:
Train-A and train-B crosses each other in 8 seconds, while running in opposite direction. Train-B crosses a pole in 8.4 seconds and train-A crosses a 90 meters long tunnel in 12 seconds. If speed of train-A is 15 km/hr more than the speed of train-B, then find the ratio of length of train-A to length of train-B.
(a) 8 : 7
(b) 11 : 7
(c) 5 : 4
(d) 3 : 2
(e) None of the above.
In such questions, we should form equations. Here you would have to form >3 equations and then remember that speed is given in km/hr while time spoken about is in seconds. So, not likely in GMAT in present form. But can help you in clearance of concepts in SPEED AND DISTANCE.So let us form equations first..
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Train-A and train-B crosses each other in 8 seconds, while running in opposite direction.
Let the length be x & y and speeds be A and B respectively. 'Running in opposite directions' means we have to add the speeds as they are moving towards each other.
so, speed = A+B and distance traveled=x+y.......Time = \(8=\frac{x+y}{A+B}......x+y=8A+8B\)....(i)
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Train-B crosses a pole in 8.4 seconds
So speed = B and distance traveled=y.......Time = \(8.4=\frac{y}{B}......y=8.4B\) ....(ii)
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train-A crosses a 90 meters long tunnel in 12 seconds
So speed = A and distance traveled=x+90.......Time = \(12=\frac{x+90}{A}......x+90=12A.....x=12A-90\) ....(iii)
Substitute values of x and y from (ii) and (iii) in (i).....\(x+y=8A+8B........8.4B+12A-90=8A+8B.........4A+0.4B=90\)......(iv)
Finally,
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speed of train-A is 15 km/hr more than the speed of train-B
As we have taken speeds in m/s, convert 15km/h in m/s......\(\frac{15km}{h}=\frac{15*1000m}{60*60sec}=\frac{15*5}{18}=\frac{25}{6}\)
So \(A=B+\frac{25}{6}\)...(v)
Substitute value of A in (iv)..
\(4A+0.4B=90.......0.4B+4(B+\frac{25}{6})=90.....2.4B+24B+100=540.....26.4B=540-100=440.....B=\frac{44*2*5}{44*0.6}=\frac{50}{3}\),
so from (ii) \(y=8.4B=8.4*\frac{50}{3}=2.8*50=140\)
and \(A=B+\frac{25}{6}=\frac{50}{3}+\frac{25}{6}=\frac{125}{6}\)
So from (iii) \(x=12A-90=12*\frac{125}{6}-90=250-90=160\)
We are looking for \(\frac{x}{y}=\frac{160}{140}=\frac{8}{7}\)
A