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Re: At Joe's candy store, the total cost of 1 gumball and 1 lollipop is $0 [#permalink]
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1G + 1L = $0.74.....(1)
1C + 1L = $0.92.....(2)
1G +1C = $1.24......(3)

Subtracting 1 from 2 gives 1C - 1G = $0.18
Adding this to 3 gives 2C = $1.42
Or 1C = $0.71

E is the answer.
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Re: At Joe's candy store, the total cost of 1 gumball and 1 lollipop is $0 [#permalink]
Bunuel wrote:
At Joe's candy store, the total cost of 1 gumball and 1 lollipop is $0.74. The total cost of 1 chocolate bar and 1 lollipop is $0.92. The total cost of 1 gumball and 1 chocolate bar is $1.24. What is the cost in dollars of 1 chocolate bar?

A. 0.53
B. 0.59
C. 0.63
D. 0.67
E. 0.71


\(g + l = 0.74\)
\(c + l = 0.92\)
\(g + c = 1.24\)

Add the 3 equations -

\(2g + 2c + 2l = 2.9\)

Or, \(g + c + l = 1.45\)

Now, subtract -

\(c = ( g + c + l ) - ( g + l )\)

Or, \(c = 1.45 - 0.74\)

Or, \(c = 0.71\), Answer must be (E)
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Re: At Joe's candy store, the total cost of 1 gumball and 1 lollipop is $0 [#permalink]
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Bunuel wrote:
At Joe's candy store, the total cost of 1 gumball and 1 lollipop is $0.74. The total cost of 1 chocolate bar and 1 lollipop is $0.92. The total cost of 1 gumball and 1 chocolate bar is $1.24. What is the cost in dollars of 1 chocolate bar?

A. 0.53
B. 0.59
C. 0.63
D. 0.67
E. 0.71


Solution:

Let G, L and C be the cost of 1 gumball, 1 lollipop and 1 chocolate bar, respectively. We can create the equations:

G + L = 0.74

C + L = 0.92

and

G + C = 1.24

Adding the 3 equations together, we have:

2G + 2L + 2C = 2.9

G + L + C = 1.45

Since G + L = 0.74, we have


0.74 + C = 1.45

C = 0.71

Answer: E
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Re: At Joe's candy store, the total cost of 1 gumball and 1 lollipop is $0 [#permalink]
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Re: At Joe's candy store, the total cost of 1 gumball and 1 lollipop is $0 [#permalink]
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