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There are 16 stones in a bowl: 4 are painted orange, 3 green and the

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Bunuel
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There are 16 stones in a bowl: 4 are painted orange, 3 green and the [#permalink] New post   31 Mar 2022, 04:00
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There are 16 stones in a bowl: 4 are painted orange, 3 green and the rest purple. What is the probability of getting first an orange and then a purple stone if you choose two stones at random without replacement ?

(A) 9/80
(B) 3/64
(C) 9/64
(D) 1/20
(E) 3/20
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E
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helipatel91198
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Re: There are 16 stones in a bowl: 4 are painted orange, 3 green and the [#permalink] New post   06 May 2022, 15:19
How do you guess whether the question asks for with replacement or without.
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Re: There are 16 stones in a bowl: 4 are painted orange, 3 green and the [#permalink] New post   08 Aug 2022, 06:56
No. Of orange : 4
No. of green : 3
No.of purple : 9

Probability of first getting an orange = 4/16
Probability of then getting purple, without replacement = 9/15 (denominator is 15 since, 1 orange is subtracted from total 16, since we chose it in the first instance)

Hence, probability of first getting an orange and then purple, WITHOUT REPLACEMENT = 4/16 * 9/15 = 3/20

Also, if with replacement,
then, probability of first getting an orange and then purple, WITH replacement = 4/16 * 9/16 = 9/64
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JeffTargetTestPrep
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Re: There are 16 stones in a bowl: 4 are painted orange, 3 green and the [#permalink] New post   08 Sep 2023, 04:01
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Bunuel wrote:
There are 16 stones in a bowl: 4 are painted orange, 3 green and the rest purple. What is the probability of getting first an orange and then a purple stone if you choose two stones at random without replacement ?

(A) 9/80
(B) 3/64
(C) 9/64
(D) 1/20
(E) 3/20


# of total = 16
# of orange = 4
# of green = 3
# of purple = 16 – 4 – 3 = 9

P(1st orange & 2nd purple) = P(1st orange) × P(2nd purple|1st orange) =

4/16 × 9/15 = 3/20

Answer: E
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Re: There are 16 stones in a bowl: 4 are painted orange, 3 green and the [#permalink]
08 Sep 2023, 04:01
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