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Working at a constant rate, pipe B can fill a container in 100 minutes

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Bunuel
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Working at a constant rate, pipe B can fill a container in 100 minutes [#permalink] Working at a constant rate, pipe B can fill a container in 100 minutes   01 Nov 2023, 01:30
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Working at a constant rate, pipe B can fill a container in 100 minutes. How many minutes does it take pipe A, working at its own constant rate, to fill the same container?

(1) Pipe A and pipe B together fill the container in one-fourth the time it takes pipe A alone.

(2) Pipe A and pipe B together fill the container in three-fourths the time it takes pipe B alone.


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samkelvin
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Re: Working at a constant rate, pipe B can fill a container in 100 minutes [#permalink] Working at a constant rate, pipe B can fill a container in 100 minutes   04 Nov 2023, 12:24
how from statement A we can get answer
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moxnguyen
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Re: Working at a constant rate, pipe B can fill a container in 100 minutes [#permalink] Working at a constant rate, pipe B can fill a container in 100 minutes   06 Nov 2023, 09:39
denote a as number of minute that pipe A fill the container alone
from (i) we have (1/100 + 1/a)=4*1/a
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pablovaldesvega
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Re: Working at a constant rate, pipe B can fill a container in 100 minutes [#permalink] Working at a constant rate, pipe B can fill a container in 100 minutes   11 Nov 2023, 06:01
Bunuel wrote:
Working at a constant rate, pipe B can fill a container in 100 minutes. How many minutes does it take pipe A, working at its own constant rate, to fill the same container?

(1) Pipe A and pipe B together fill the container in one-fourth the time it takes pipe A alone.

(2) Pipe A and pipe B together fill the container in three-fourths the time it takes pipe B alone.


This is a Data Sufficiency Butler Question



can someone please provide an explanation?
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Re: Working at a constant rate, pipe B can fill a container in 100 minutes [#permalink] Working at a constant rate, pipe B can fill a container in 100 minutes   27 May 2024, 21:25
Here you go my friend...
It takes pipe A, working at its own constant rate, to fill the same container in a 'a' minutes.
Pipe A and pipe B together fill the container in , 100a / (100 + a ) minutes.
Statement A says , 
a/ 4 = 100*a / (100 +a )
a=300

Statement B says,
100a / (100 +a ) = 3/4 * 100
25a = 7500
a=300

D is the answer as from each statement we get the answer that it takes  pipe A, working at its own constant rate, 300 minutes to fill the same container.


pablovaldesvega wrote:
Bunuel wrote:
Working at a constant rate, pipe B can fill a container in 100 minutes. How many minutes does it take pipe A, working at its own constant rate, to fill the same container?

(1) Pipe A and pipe B together fill the container in one-fourth the time it takes pipe A alone.

(2) Pipe A and pipe B together fill the container in three-fourths the time it takes pipe B alone.




can someone please provide an explanation?

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Re: Working at a constant rate, pipe B can fill a container in 100 minutes [#permalink]
27 May 2024, 21:25
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Bunuel
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