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In a battle 70% of the combatants lost an eye, 80% an ear,

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az780
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In a battle 70% of the combatants lost an eye, 80% an ear, [#permalink] New post   19 Mar 2008, 23:59
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In a battle 70% of the combatants lost an eye, 80% an ear, 75% an arm, 85% a leg, x% lost all four limbs. The minimum value of x is?

Please advise the best way to solve this problem



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Re: In a battle 70% of the combatants lost an eye, 80% an ear, [#permalink] New post   20 Mar 2008, 00:53
85%
leg is subset of 4 limbs ( i suppose ^^). So those lost 4 limbs sure lost leg
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Re: In a battle 70% of the combatants lost an eye, 80% an ear, [#permalink] New post   20 Mar 2008, 01:15
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az780 wrote:
In a battle 70% of the combatants lost an eye, 80% an ear, 75% an arm, 85% a leg, x% lost all four limbs. The minimum value of x is?


terrible :(
it is a strange question...
So, 70% an eye, 80% an ear, 75% an arm, 85% a leg.

1. an eye and and an ear: p=[50%,70%]
2. (an eye and and an ear) and an arm: p=[25%,70%]
3. ((an eye and and an ear) and an arm) and a leg: p=[10%,70%]

Therefore, min: 10%, max: 70%
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Re: In a battle 70% of the combatants lost an eye, 80% an ear, [#permalink] New post   20 Mar 2008, 02:15
walker wrote:
az780 wrote:
In a battle 70% of the combatants lost an eye, 80% an ear, 75% an arm, 85% a leg, x% lost all four limbs. The minimum value of x is?


terrible :(
it is a strange question...
So, 70% an eye, 80% an ear, 75% an arm, 85% a leg.

1. an eye and and an ear: p=[50%,70%]
2. (an eye and and an ear) and an arm: p=[25%,70%]
3. ((an eye and and an ear) and an arm) and a leg: p=[10%,70%]

Therefore, min: 10%, max: 70%


This is really funny problem. I can not stand when I read it. :P :P :P
Anyway, Walker! I try to but can not follow your logic! Sets always make me confused! Please give me some detail. Your approach strange also :lol:
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Re: In a battle 70% of the combatants lost an eye, 80% an ear, [#permalink] New post   20 Mar 2008, 02:39
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sondenso wrote:
This is really funny problem. I can not stand when I read it. :P :P :P
Anyway, Walker! I try to but can not follow your logic! Sets always make me confused! Please give me some detail. Your approach strange also :lol:


:)
1. Let we have two attributes: A and B.
2. Let a% of people have A and b% of people have B.
3. we will try to find max and min ab% (the percentage of people that have two attributes)

I'll try to draw:

the maximum configuration:
|aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa------------------| 100%
|bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb--------------| 100%
max=min(a,b)

the minimum configuration:
|aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa------------------| 100%
|---------------bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb| 100%
min=b-(100-a)=a+b-100. if min<0 then min have to be 0

for example, a=75%, b=87%

max=min(75%,87%)=75%
min=87%-(100%-75%)=62%
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Re: In a battle 70% of the combatants lost an eye, 80% an ear, [#permalink] New post   20 Mar 2008, 19:34
walker wrote:
sondenso wrote:
This is really funny problem. I can not stand when I read it. :P :P :P
Anyway, Walker! I try to but can not follow your logic! Sets always make me confused! Please give me some detail. Your approach strange also :lol:


:)
1. Let we have two attributes: A and B.
2. Let a% of people have A and b% of people have B.
3. we will try to find max and min ab% (the percentage of people that have two attributes)

I'll try to draw:

the maximum configuration:
|aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa------------------| 100%
|bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb--------------| 100%
max=min(a,b)

the minimum configuration:
|aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa------------------| 100%
|---------------bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb| 100%
min=b-(100-a)=a+b-100. if min<0 then min have to be 0

for example, a=75%, b=87%

max=min(75%,87%)=75%
min=87%-(100%-75%)=62%


Thank you Walker, you are great! :thanks
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Re: In a battle 70% of the combatants lost an eye, 80% an ear, [#permalink] New post   06 Jul 2017, 07:39
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Re: In a battle 70% of the combatants lost an eye, 80% an ear, [#permalink]
06 Jul 2017, 07:39
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