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C is correct, The reason is from the first statement the two lines, would either cross the X axis at a point where x>0 or here x<0. In both the cases we cannot determine what would be the product of the slopes.
Coming to 2nd statement since it is negative, it means that one line crosses the y axis at a point where y>0 and the other line crosses the y axis at a point where y<0. This situation alone cant help. If we combine both, then you will find that it is possible only when x>0 - from teh inference of statement 1. best , is if you can draw a diagram.
Award points if you feel. Let me know for any further clarifications
the basic equation of a line is y = mx + c. where the slope is m, y-intercept is c and x-intercept is -c/m let's say:
l is y = m1x + c1 with y-intercept = c1 and x-intercept = -c1/m1 k is y = m2x + c2 with y-intercept = c2 and x-intercept = -c2/m2
statement I - c1c2/m1m2 > 0. does not say anything about c1c2 so we cannot say if m1m2 is negative or not
statement I - c1c2 < 0. does not say anything about m1 and m2 so we cannot say if m1m2 is negative or not.
I and II - if c1c2 < 0 then m1m2 has to be negative.
Thus C
This is what I did. How ever, I was wondering (4,3) were never used when I solved. Then I started thinking Did I miss some thing here?
What is the OA?
The point is given as a trap to attract people to draw lines and form cases and waste time. without the point too the question would remain the same, just that when they find no other way, people would straightaway jump to the equation based approach. Just my feeling, I might be terribly wrong. OA is C, see image in the first post.
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