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In the figures above, if the area

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study
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In the figures above, if the area [#permalink] New post   24 Dec 2008, 07:00
another one from gmatprep

Attachment:
qs.doc




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Re: In the figures above, if the area [#permalink] New post   24 Dec 2008, 11:43
study wrote:
another one from gmatprep

Attachment:
qs.doc


\(1/2*S*H = 2 * 1/2*s*h\)

S/s=H/h (for similar triangles)

\(S^2= 2*s^2\)
\(S=sqrt(2)*s\)

C is the answer.
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Re: In the figures above, if the area [#permalink] New post   29 Dec 2008, 09:29
can someone give a more detailed explanation.

how does suresh get s^2??
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Re: In the figures above, if the area [#permalink] New post   29 Dec 2008, 11:02
The ratio of the area is similarity sqared.

For example:

Triangle 1 area: 10
base: 5
height: 4

Triagnle 2 area: 40
base: 2(5)=10
height: 2(4)=8

Similiartiy between triangle 1 and 2 is 1/2 since both triangle 2's base and height are twice the triangle 1's.
10/40 = (1^2)/(2^2)
1/4 = 1/4

Now, going back to the question.

1/2 = (1/sq. rt 2)^2
Similarity between the smaller triangle and the bigger triangle is sq. rt. 2
Therefore S = sq. rt 2 * s.
Answer is C.
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Re: In the figures above, if the area [#permalink] New post   29 Dec 2008, 11:11
Thanks for your explanation.

How do you get portion highlighted in red?:
10/40 = (1^2)/(2^2)

shouldnt it be 10/40 = 5/10?

and i still dont understand how you are using this information to derive sqroot2 as teh answer.

thanks in advnce for your explanation



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Re: In the figures above, if the area [#permalink]
29 Dec 2008, 11:11
Moderator:
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