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In the figures above, if the area

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Senior Manager
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Joined: 05 Oct 2008
Posts: 267

Kudos [?]: 550 [0], given: 22

In the figures above, if the area [#permalink]

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New post 24 Dec 2008, 07:00
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

another one from gmatprep

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qs.doc [63.5 KiB]
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Kudos [?]: 550 [0], given: 22

SVP
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Joined: 07 Nov 2007
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Location: New York
Re: geo-gmatprep [#permalink]

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New post 24 Dec 2008, 11:43
study wrote:
another one from gmatprep

Attachment:
qs.doc


\(1/2*S*H = 2 * 1/2*s*h\)

S/s=H/h (for similar triangles)

\(S^2= 2*s^2\)
\(S=sqrt(2)*s\)

C is the answer.
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Kudos [?]: 1089 [0], given: 5

Senior Manager
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Joined: 05 Oct 2008
Posts: 267

Kudos [?]: 550 [0], given: 22

Re: geo-gmatprep [#permalink]

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New post 29 Dec 2008, 09:29
can someone give a more detailed explanation.

how does suresh get s^2??

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Intern
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Re: geo-gmatprep [#permalink]

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New post 29 Dec 2008, 11:02
The ratio of the area is similarity sqared.

For example:

Triangle 1 area: 10
base: 5
height: 4

Triagnle 2 area: 40
base: 2(5)=10
height: 2(4)=8

Similiartiy between triangle 1 and 2 is 1/2 since both triangle 2's base and height are twice the triangle 1's.
10/40 = (1^2)/(2^2)
1/4 = 1/4

Now, going back to the question.

1/2 = (1/sq. rt 2)^2
Similarity between the smaller triangle and the bigger triangle is sq. rt. 2
Therefore S = sq. rt 2 * s.
Answer is C.

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Senior Manager
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Joined: 05 Oct 2008
Posts: 267

Kudos [?]: 550 [0], given: 22

Re: geo-gmatprep [#permalink]

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New post 29 Dec 2008, 11:11
Thanks for your explanation.

How do you get portion highlighted in red?:
10/40 = (1^2)/(2^2)

shouldnt it be 10/40 = 5/10?

and i still dont understand how you are using this information to derive sqroot2 as teh answer.

thanks in advnce for your explanation

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Re: geo-gmatprep   [#permalink] 29 Dec 2008, 11:11
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In the figures above, if the area

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