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Standard Normal Probability Distribution question
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06 Jul 2010, 12:49
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Hi,
Can someone advise me if my calculation for the below question is correct.
Q1. An HR Manager is concerned about the absenteeism of hourly employees, especially on Wednesday in the summer months. He has collected data for Wednesday in May over the past 6 years as follows:
Find the mean number of employees absent as well as the standard deviation. If absenteeism on Wednesday in May is felt to be normally distributed, what is the probability there would be more than 112 people absent on a Wednesday in May?
My calculation:
A. Mean = 96 B. Standard Deviation = 12.41 or 12
C. Probability of more than 112 people absent on Wednesday in month of May
where: mean = 96 std. dev. = 12 X = 112
Z score computation:
z= X - mean / std.dev
z = 112 - 96 / 12
z = 1.33 = 0.4082
On Z distribution table, the value of 1.33 is 0.4082
Since X is greater than the mean value
P(X) = 0.5 + Z = 0.5 + 0.4082 = 0.91 or 91%
Appreciate for a positive feedback.
Thanks.
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Re: Standard Normal Probability Distribution question [#permalink]