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Paula and Quentin are two members of an eight-member committee.

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Senior Manager
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Joined: 18 Jun 2018
Posts: 267
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Paula and Quentin are two members of an eight-member committee.  [#permalink]

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New post 10 Sep 2018, 04:09
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Difficulty:

  15% (low)

Question Stats:

77% (01:04) correct 23% (01:19) wrong based on 31 sessions

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Paula and Quentin are two members of an eight-member committee. If the committee selects its president and secretary at random, and the same member cannot hold both positions, what is the probability that Paula is selected as president and Quentin is selected as secretary?

A) \(\frac{1}{64}\)

B) \(\frac{1}{56}\)

C) \(\frac{1}{49}\)

D) \(\frac{1}{36}\)

E) \(\frac{1}{24}\)
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Joined: 02 Sep 2015
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Re: Paula and Quentin are two members of an eight-member committee.  [#permalink]

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New post 10 Sep 2018, 04:26
Selecting paula out of 8 member committee: \(1C1/8C1\) = \(1/8\)
Selecting Quentin out of 7 member committee: \(1C1/7C1\) = \(1/7\) since paula is already selected for presidency only 7 ppl are left for secretary
Selecting both: \(1/8 * 1/7\) = \(1/56\)
Answer: B
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Re: Paula and Quentin are two members of an eight-member committee.  [#permalink]

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New post 10 Sep 2018, 05:41
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Bismarck wrote:
Paula and Quentin are two members of an eight-member committee. If the committee selects its president and secretary at random, and the same member cannot hold both positions, what is the probability that Paula is selected as president and Quentin is selected as secretary?

A) \(\frac{1}{64}\)

B) \(\frac{1}{56}\)

C) \(\frac{1}{49}\)

D) \(\frac{1}{36}\)

E) \(\frac{1}{24}\)


P(Paula becomes president and Quentin becomes secretary) = P(Paula becomes president) x P(Quentin becomes secretary)
= 1/8 x 1/7
= 1/56

Answer: B

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Brent
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Re: Paula and Quentin are two members of an eight-member committee.   [#permalink] 10 Sep 2018, 05:41
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Paula and Quentin are two members of an eight-member committee.

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