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# PFA 2question..JPG

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Manager
Joined: 09 Oct 2008
Posts: 93

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22 Oct 2008, 20:36
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

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Senior Manager
Joined: 04 Aug 2008
Posts: 370

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22 Oct 2008, 22:15
250miles/30m-g/12gallons/1

=250/30*12

=25/36
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Intern
Joined: 03 Mar 2008
Posts: 44

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22 Oct 2008, 22:16
vishalgc wrote:
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(i)
x + (1.1 x) 10 = 132000
x = 11000

(ii)
250 miles implies 25/3 gallons used
implies (25/3)/12 = 25/36 fraction used of full tank

Last edited by kandyhot27 on 22 Oct 2008, 22:17, edited 1 time in total.
Senior Manager
Joined: 29 Mar 2008
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22 Oct 2008, 22:17
1) Pick an answer and work backwards.
Let the least population be 10,900. Hence, rest of the 10 districts can have a population of 11990 each. Now, 10,900 + 10(11990) = 130800, but the total population is 132000.
Let the least population be 11,000. Hence, rest of the 10 districts can have a population of 12100 each. Now, 11,000+10(12100) = 132000 (which is the total population).
Hence 11,000. (No need to try 11100 as this will exceed the given population of 132000.)

Another way of looking at this is- The district 1 will have the least population and rest of the 10 districts will have a population of 10% higher than district 1 to meet the given condition.
Let X be the pupulation of district 1 (Least)
13200 = (1+10/100)X*10 + X
Solving for X, gives 11,000.

2) The car travels 250 miles (i.e Distance = Speed * Time =50 *5)
The car can travel 30 miles in 1G of gasolene.
In order to travel 250 miles, the car will need 250/30= 25/3 Gallons.

Fraction of gasolene used to total = (25/3)/12 = 25/36.
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Re: simple maths problem   [#permalink] 22 Oct 2008, 22:17
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# PFA 2question..JPG

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