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Relative to a group of other airlines, an airlines degree of

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felippemed
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Relative to a group of other airlines, an airlines degree of [#permalink] Relative to a group of other airlines, an airlines degree of   Updated on: 08 Nov 2023, 02:58
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74% (02:26) correct 26% (02:50) wrong based on 556 sessions
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Relative to a group of other airlines, an airline’s degree of competition, c, for daily flights from City X to Destination Y is given by the formula \(c=\frac{T}{f}+\frac{n}{4}\)​, where the airline has f daily flights from City X to Destination Y, n of the other airlines in the group each have at least 1 daily flight from City X to Destination Y, and these n airlines have a combined total of T daily flights from City X to Destination Y. According to the table above, what is Airline A’s degree of competition, relative to Airlines B, C, and D, for daily flights from City X to Los Angeles?


(A) 1
(B) 5/4
(C) 7/4
(D) 2
(E) 9/4

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Originally posted by felippemed on 13 Sep 2016, 12:45.
Last edited by Bunuel on 08 Nov 2023, 02:58, edited 5 times in total.
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EMPOWERgmatRichC
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Re: Relative to a group of other airlines, an airlines degree of [#permalink] Relative to a group of other airlines, an airlines degree of   13 Sep 2016, 16:48
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Hi felippemed,

To start, we'll need the 5 answer choices for reference:

A) 1
B) 5/4
C) 7/4
D) 2
E) 9/4

This question is essentially a "symbolism" question (albeit with an equation instead of a symbol): you're told what each variable in the equation "means" and then we're asked to do a simple calculation using data from a table:

We're given the equation: T/F + N/4

We're told to calculate (using that equation) for Airline A and Los Angeles. So, we just have to pull data from the table and plug in the numbers:

F = number of flights that Airline A has to Los Angeles
F = 4
N = number of OTHER airlines with at least 1 flight to Los Angles.
N = 3
T = combined flights to Los Angeles from the other airlines
T = 5

Now, plug in:

5/4 + 3/4 = 8/4 = 2

Final Answer:
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rudra316
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Re: Relative to a group of other airlines, an airlines degree of [#permalink] Relative to a group of other airlines, an airlines degree of   16 Sep 2016, 06:59
From the Data we have
f = 4;
T = 5;
n = 3;
Substituting in the equation for degree of competition,
c = \(\frac{5}{4} + \frac{3}{4}\)
c = 2
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Re: Relative to a group of other airlines, an airlines degree of [#permalink] Relative to a group of other airlines, an airlines degree of   14 Mar 2020, 12:12
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EMPOWERgmatRichC wrote:
Hi felippemed,

To start, we'll need the 5 answer choices for reference:

A) 1
B) 5/4
C) 7/4
D) 2
E) 9/4

This question is essentially a "symbolism" question (albeit with an equation instead of a symbol): you're told what each variable in the equation "means" and then we're asked to do a simple calculation using data from a table:

We're given the equation: T/F + N/4

We're told to calculate (using that equation) for Airline A and Los Angeles. So, we just have to pull data from the table and plug in the numbers:

F = number of flights that Airline A has to Los Angeles
F = 4
N = number of OTHER airlines with at least 1 flight to Los Angles.
N = 3
T = combined flights to Los Angeles from the other airlines
T = 5

Now, plug in:

5/4 + 3/4 = 8/4 = 2

Final Answer:
Show Spoiler
D


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Rich





Rich, why do we use 3 for N and not 4? Not sure I am following that
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Re: Relative to a group of other airlines, an airlines degree of [#permalink] Relative to a group of other airlines, an airlines degree of   14 Mar 2020, 13:30
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Hi BradyMVP,

The prompt gives us a specific definition for each of the variables involved - and that we can define an airline's "degree of competition (C)" using those variables.

We're asked to find the value of "C" for Airline A. The prompt tells us the value of "N" is equal to the total number of OTHER airlines that fly to the same city. Since Airline A flies to Los Angeles - and we're calculating the level of competition for Airline A - we should NOT include that airline as part of the value of N. Based on the data in the table, we can see that Airlines B, C and D all fly to Los Angeles; that's a total of 3 OTHER cities, so the value of N = 3.

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Re: Relative to a group of other airlines, an airlines degree of [#permalink] Relative to a group of other airlines, an airlines degree of   20 May 2024, 06:09
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Annoying question but just sort out what each variable equals:

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Re: Relative to a group of other airlines, an airlines degree of [#permalink] Relative to a group of other airlines, an airlines degree of   10 Jun 2024, 04:59
\(­c = \frac{T}{f} + \frac{n}{4}\)

n: number of other airlines also has same route X - LA ==> n = 3
f: A's number of flights => f = 4
T: number of flights of the n airlines => T = 2 + 2 + 1  = 5

\(c_A = \frac{5}{4} + \frac{3}{4} = \frac{8}{4} = 2\)­
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Re: Relative to a group of other airlines, an airlines degree of [#permalink]
10 Jun 2024, 04:59
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