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Manager
Joined: 28 Jul 2011
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Salad dressing A is made up of 30% vinegar and 70% oil, and salad dres
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24 Aug 2011, 04:04
Question Stats:
76% (01:43) correct 24% (02:34) wrong based on 318 sessions
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Salad dressing A is made up of 30% vinegar and 70% oil, and salad dressing B contains 10% vinegar and 90% oil. If the 2 dressing are combined to produce a salad dressing that is 15% vinegar, dressing A comprises what % of the new dressing? A. 15% B. 20% C. 25% D. 40% E. 55%
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Re: Salad dressing A is made up of 30% vinegar and 70% oil, and salad dres
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24 Aug 2011, 06:07
There is one trick you can use to solve mixture problems very fast. quantity of Vinegar in A: 30%, in B: 10% and in (A+B): 15% We need (1510)/(3010) = 5/20 = 1/4 or 25% of A.
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Re: Salad dressing A is made up of 30% vinegar and 70% oil, and salad dres
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24 Aug 2011, 05:53
they way I solved it: quantity of Vinegar => 30% A + 10% B = 15% (A + B) 30%A + 10%B = 15%A + 15%B 15%A = 5%B B = 15%A / 5% = 3A if B = 3A => A+B = 4A as a result A / (A+B) = A / 4A = 0.25 = 25%



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Re: Salad dressing A is made up of 30% vinegar and 70% oil, and salad dres
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24 Aug 2011, 06:13
use the graph method to solve it quickly
B has 30% vinegar, A  10% and the new dressing  15% 101530 therefore intuitively you can say that there is a lot less of dressing A than dressing B in the new mix since 15 is closer to 10 than 30 is. How much lesser? (1510)/(3010) = 5/20 = 25%



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Re: Salad dressing A is made up of 30% vinegar and 70% oil, and salad dres
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24 Aug 2011, 11:05
The total combination must be 100%. Let X% of dressing 1 is used. 30 * x + 10 * (100x) = 15*100 solving, x= 25% C is the answer.
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Re: Salad dressing A is made up of 30% vinegar and 70% oil, and salad dres
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25 Aug 2011, 04:23
Thank everyone, appreciate your help. those were some really good short hands.
Regards,



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Re: Salad dressing A is made up of 30% vinegar and 70% oil, and salad dres
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08 Sep 2011, 08:59
alexgmd wrote: they way I solved it: quantity of Vinegar => 30% A + 10% B = 15% (A + B) 30%A + 10%B = 15%A + 15%B 15%A = 5%B B = 15%A / 5% = 3A if B = 3A => A+B = 4A as a result A / (A+B) = A / 4A = 0.25 = 25% This is how I worked it out. Walker, can you please explain your method a bit?
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Re: Salad dressing A is made up of 30% vinegar and 70% oil, and salad dres
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19 Oct 2014, 21:05
kuttingchai wrote: Salad dressing A is made up of 30% vinegar and 70% oil, and salad dressing B contains 10% vinegar and 90% oil. If the 2 dressing are combined to produce a salad dressing that is 15% vinegar, dressing A comprises what % of the new dressing?
A. 15% B. 20% C. 25% D. 40% E. 55% Here is a post that discusses how to solve such questions in seconds: http://www.veritasprep.com/blog/2011/04 ... mixtures/The copper nickel example is exactly like this one. w1/w2 = (A2  Aavg)/(Aavg  A1) wA/wB = (10  15)/(15  30) = 1/3 So ratio of salad dressing A to salad dressing B is 1:3 i.e. salad dressing A makes up 1/4 = 25% of the mix. Answer (C)
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Re: Salad dressing A is made up of 30% vinegar and 70% oil, and salad dres
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22 Feb 2018, 16:34
kuttingchai wrote: Salad dressing A is made up of 30% vinegar and 70% oil, and salad dressing B contains 10% vinegar and 90% oil. If the 2 dressing are combined to produce a salad dressing that is 15% vinegar, dressing A comprises what % of the new dressing?
A. 15% B. 20% C. 25% D. 40% E. 55% We can let the amount of dressing A = a and the amount of dressing B = b, thus: 0.3a + 0.1b = 0.15(a + b) 30a + 10b = 15a + 15b 15a = 5b 3a = b So dressing A is a/(a + b) = a/(a + 3a) = 1/4 = 25% of the new dressing. Answer: C
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Re: Salad dressing A is made up of 30% vinegar and 70% oil, and salad dres &nbs
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