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# stragedy needed?

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Manager
Joined: 01 Dec 2007
Posts: 52

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24 Sep 2008, 02:59
i need fool proof stragedy for solving it.

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Manager
Joined: 24 Apr 2008
Posts: 160

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24 Sep 2008, 03:03
Let x be infinity then we can write the equation as : 1 / (2+1/x) which will tend to 1/2 as

When x--> infinity ; 1/x--> 0
Manager
Joined: 01 Dec 2007
Posts: 52

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24 Sep 2008, 03:52
iamcartic wrote:
Let x be infinity then we can write the equation as : 1 / (2+1/x) which will tend to 1/2 as

When x--> infinity ; 1/x--> 0

didn't understand this approach please clarify it more.
Senior Manager
Joined: 10 Mar 2008
Posts: 341

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24 Sep 2008, 04:00
Substitute 3000 for x in the equation, disregard 1 from the denominator (since you only need a close approximation) an2d solve the equation. You should end up with 1/2, which I believe is the correct answer
SVP
Joined: 17 Jun 2008
Posts: 1502

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25 Sep 2008, 12:25
blover wrote:
i need fool proof stragedy for solving it.

What the questions tells that x is a large enough number compared to 1 and hence (2x+1) can be approximated to 2x.

Thus, the given expression will be close to 1/2.
Intern
Joined: 12 Sep 2008
Posts: 23

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25 Sep 2008, 12:51
I agree w/ vakunder. This is how I understood the problem and solved it. Substitute 3001 for x and solve the equation and you'll get 3001/6003. Since x is greater than 3000, the outcome will be greater than 3000/6001. You can see here the greater the x is, the closer the outcome will be to 1/2 (ie. 3000/6001, 4000/8001, 5000/10001, etc.). Therefore the value of x/(2x+1) is closer to 1/2 as x increases.

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This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.
Re: stragedy needed?   [#permalink] 25 Sep 2008, 12:51
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# stragedy needed?

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