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stragedy needed?

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Manager
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stragedy needed? [#permalink]

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New post 24 Sep 2008, 02:59
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

i need fool proof stragedy for solving it.
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Manager
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Re: stragedy needed? [#permalink]

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New post 24 Sep 2008, 03:03
Let x be infinity then we can write the equation as : 1 / (2+1/x) which will tend to 1/2 as

When x--> infinity ; 1/x--> 0

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Re: stragedy needed? [#permalink]

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New post 24 Sep 2008, 03:52
iamcartic wrote:
Let x be infinity then we can write the equation as : 1 / (2+1/x) which will tend to 1/2 as

When x--> infinity ; 1/x--> 0


didn't understand this approach please clarify it more.

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Re: stragedy needed? [#permalink]

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New post 24 Sep 2008, 04:00
Substitute 3000 for x in the equation, disregard 1 from the denominator (since you only need a close approximation) an2d solve the equation. You should end up with 1/2, which I believe is the correct answer

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Re: stragedy needed? [#permalink]

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New post 25 Sep 2008, 12:25
blover wrote:
i need fool proof stragedy for solving it.


What the questions tells that x is a large enough number compared to 1 and hence (2x+1) can be approximated to 2x.

Thus, the given expression will be close to 1/2.

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Re: stragedy needed? [#permalink]

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New post 25 Sep 2008, 12:51
I agree w/ vakunder. This is how I understood the problem and solved it. Substitute 3001 for x and solve the equation and you'll get 3001/6003. Since x is greater than 3000, the outcome will be greater than 3000/6001. You can see here the greater the x is, the closer the outcome will be to 1/2 (ie. 3000/6001, 4000/8001, 5000/10001, etc.). Therefore the value of x/(2x+1) is closer to 1/2 as x increases.

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Re: stragedy needed?   [#permalink] 25 Sep 2008, 12:51
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