Bunuel wrote:

Tahboob Corporation manufactures only two models of kitchens, model A and model B. The selling price of model A is $1600, which is 40 percent of the selling price of model B. If the manufacturer sells 250 kitchens, 3/5 of which are model B, what is the total revenue from the sale of kitchens?

A. $350,000

B. $500,000

C. $600,000

D. $640,000

E. $760,000

To simplify the arithmetic, I removed two zeros from price of A and B (divided by 100)

Total revenue =

(Qty of A)(price of A) + (Qty of B)(price of B)Price of A = $16

$16 = \(\frac{4}{10}\) Price of B

Price of B = $16 * \(\frac{10}{4}=\) $40

Quantity of B: \(\frac{3}{5}\) of 250 = 150

Quantity of A: (250 - 150) = 100

Total revenue:

(16)(100) + (150)(40) =

(1,600 + 6,000) = $7,200 [add 2 zeros] =

$720,000

Answer E

_________________

In the depths of winter, I finally learned

that within me there lay an invincible summer.

-- Albert Camus, "Return to Tipasa"