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The attendance on the first day of a 3day festival was 20% greater
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20 Mar 2018, 22:00
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The attendance on the first day of a 3day festival was 20% greater than the attendance on the final day of the festival. If the attendance on the first day was 11,418, what was the attendance on the final day of the festival? (A) 3,806 (B) 5,190 (C) 9,134 (D) 9,515 (E) 11,194
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Re: The attendance on the first day of a 3day festival was 20% greater
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20 Mar 2018, 22:02
Bunuel wrote: The attendance on the first day of a 3day festival was 20% greater than the attendance on the final day of the festival. If the attendance on the first day was 11,418, what was the attendance on the final day of the festival?
(A) 3,806 (B) 5,190 (C) 9,134 (D) 9,515 (E) 11,194 4. Percents and Iterest For more check: ALL YOU NEED FOR QUANT ! ! !Ultimate GMAT Quantitative Megathread
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Re: The attendance on the first day of a 3day festival was 20% greater
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21 Mar 2018, 21:27
Bunuel wrote: The attendance on the first day of a 3day festival was 20% greater than the attendance on the final day of the festival. If the attendance on the first day was 11,418, what was the attendance on the final day of the festival?
(A) 3,806 (B) 5,190 (C) 9,134 (D) 9,515 (E) 11,194 X1,20=11 418 X=11418/1,20 X=9 515



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The attendance on the first day of a 3day festival was 20% greater
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23 Mar 2018, 10:19
Bunuel wrote: The attendance on the first day of a 3day festival was 20% greater than the attendance on the final day of the festival. If the attendance on the first day was 11,418, what was the attendance on the final day of the festival?
(A) 3,806 (B) 5,190 (C) 9,134 (D) 9,515 (E) 11,194 1) Shortcut: Day 1 is 20% = \(1.2=\frac{6}{5}\)*Day 3 Day 3's number must be divisible by 5 That leaves answers B and D Eliminate B) 5,190: Here, Day 1 is 2+ times greater than B, not 1/5 greater than Answer D (If you backsolved, i.e., used answer choice * 6/5, the shortcut would be evident quickly) 2) Equation Day 1 attendance is 20% greater than Day 3 Day 1 = 1.2*(Day3) Let x = Day 3 attendance \(11,418 = 1.2x\) \((\frac{11,148}{1.2})=(\frac{114,180}{12})=x\) \(x = 9,515\)Answer D



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Re: The attendance on the first day of a 3day festival was 20% greater
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23 Mar 2018, 11:47
Bunuel wrote: The attendance on the first day of a 3day festival was 20% greater than the attendance on the final day of the festival. If the attendance on the first day was 11,418, what was the attendance on the final day of the festival?
(A) 3,806 (B) 5,190 (C) 9,134 (D) 9,515 (E) 11,194 We can let attendance on the final day = n and create the equation: 11,418 = 1.2n 9,515 = n Answer: D
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The attendance on the first day of a 3day festival was 20% greater
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23 Mar 2018, 14:54
Let a be the attendance of crowd on Day 3. Day 1 = 1.2a = 6/5a
6a/5 = 11, 418 a = 11,418 * 5/6
No need to perform the division, we can see that 18/6 = 3 so we will get xxx3 *5 thus we are looking for unit digit of 5 in the answer choice thus D.



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Re: The attendance on the first day of a 3day festival was 20% greater
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24 Mar 2018, 07:18
Bunuel wrote: The attendance on the first day of a 3day festival was 20% greater than the attendance on the final day of the festival. If the attendance on the first day was 11,418, what was the attendance on the final day of the festival?
(A) 3,806 (B) 5,190 (C) 9,134 (D) 9,515 (E) 11,194 Attendance of Day 1 = 120% of Attendance of Final day 11418 = 120% of Attendance of Final day So, Attendance of Final day = 9515, Answer must be (D)
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Re: The attendance on the first day of a 3day festival was 20% greater
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24 Mar 2018, 12:00
Bunuel wrote: The attendance on the first day of a 3day festival was 20% greater than the attendance on the final day of the festival. If the attendance on the first day was 11,418, what was the attendance on the final day of the festival?
(A) 3,806 (B) 5,190 (C) 9,134 (D) 9,515 (E) 11,194 Let x be the attendance on Day  3. Day 1 attendance = 1.2x => 11418 =1.2x x = 9515 Option D.
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