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The attendance on the first day of a 3-day festival was 20% greater

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The attendance on the first day of a 3-day festival was 20% greater  [#permalink]

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New post 20 Mar 2018, 23:00
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Question Stats:

89% (01:36) correct 11% (02:36) wrong based on 59 sessions

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Re: The attendance on the first day of a 3-day festival was 20% greater  [#permalink]

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New post 20 Mar 2018, 23:02
Bunuel wrote:
The attendance on the first day of a 3-day festival was 20% greater than the attendance on the final day of the festival. If the attendance on the first day was 11,418, what was the attendance on the final day of the festival?

(A) 3,806
(B) 5,190
(C) 9,134
(D) 9,515
(E) 11,194


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Re: The attendance on the first day of a 3-day festival was 20% greater  [#permalink]

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New post 21 Mar 2018, 22:27
Bunuel wrote:
The attendance on the first day of a 3-day festival was 20% greater than the attendance on the final day of the festival. If the attendance on the first day was 11,418, what was the attendance on the final day of the festival?

(A) 3,806
(B) 5,190
(C) 9,134
(D) 9,515
(E) 11,194


X1,20=11 418
X=11418/1,20
X=9 515
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The attendance on the first day of a 3-day festival was 20% greater  [#permalink]

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New post 23 Mar 2018, 11:19
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Bunuel wrote:
The attendance on the first day of a 3-day festival was 20% greater than the attendance on the final day of the festival. If the attendance on the first day was 11,418, what was the attendance on the final day of the festival?

(A) 3,806
(B) 5,190
(C) 9,134
(D) 9,515
(E) 11,194

1) Shortcut: Day 1 is 20% = \(1.2=\frac{6}{5}\)*Day 3

Day 3's number must be divisible by 5
That leaves answers B and D

Eliminate B) 5,190: Here, Day 1 is 2+ times greater than B, not 1/5 greater than

Answer D
(If you backsolved, i.e., used answer choice * 6/5, the shortcut would be evident quickly)

2) Equation

Day 1 attendance is 20% greater than Day 3
Day 1 = 1.2*(Day3)
Let x = Day 3 attendance

\(11,418 = 1.2x\)
\((\frac{11,148}{1.2})=(\frac{114,180}{12})=x\)
\(x = 9,515\)


Answer D
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Re: The attendance on the first day of a 3-day festival was 20% greater  [#permalink]

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New post 23 Mar 2018, 12:47
Bunuel wrote:
The attendance on the first day of a 3-day festival was 20% greater than the attendance on the final day of the festival. If the attendance on the first day was 11,418, what was the attendance on the final day of the festival?

(A) 3,806
(B) 5,190
(C) 9,134
(D) 9,515
(E) 11,194


We can let attendance on the final day = n and create the equation:

11,418 = 1.2n

9,515 = n

Answer: D
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The attendance on the first day of a 3-day festival was 20% greater  [#permalink]

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New post 23 Mar 2018, 15:54
Let a be the attendance of crowd on Day 3.
Day 1 = 1.2a = 6/5a

6a/5 = 11, 418
a = 11,418 * 5/6

No need to perform the division, we can see that 18/6 = 3 so we will get xxx3 *5 thus we are looking for unit digit of 5 in the answer choice thus
D.
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Re: The attendance on the first day of a 3-day festival was 20% greater  [#permalink]

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New post 24 Mar 2018, 08:18
1
Bunuel wrote:
The attendance on the first day of a 3-day festival was 20% greater than the attendance on the final day of the festival. If the attendance on the first day was 11,418, what was the attendance on the final day of the festival?

(A) 3,806
(B) 5,190
(C) 9,134
(D) 9,515
(E) 11,194


Attendance of Day 1 = 120% of Attendance of Final day

11418 = 120% of Attendance of Final day

So, Attendance of Final day = 9515, Answer must be (D)
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Re: The attendance on the first day of a 3-day festival was 20% greater  [#permalink]

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New post 24 Mar 2018, 13:00
Bunuel wrote:
The attendance on the first day of a 3-day festival was 20% greater than the attendance on the final day of the festival. If the attendance on the first day was 11,418, what was the attendance on the final day of the festival?

(A) 3,806
(B) 5,190
(C) 9,134
(D) 9,515
(E) 11,194



Let x be the attendance on Day - 3.

Day 1 attendance = 1.2x
=> 11418 =1.2x

x = 9515

Option D.
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Re: The attendance on the first day of a 3-day festival was 20% greater   [#permalink] 24 Mar 2018, 13:00
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