The average (arithmetic mean) annual salary of the employees of a comp

Hi Palak, I think it should be

(65000x+80,000y)/x+y = 70,000(x+y)

Solution:

We see the average female employees’ annual salary is $10,000 greater than the overall average of all employees’ annual salary, and yet the average male employees’ annual salary is $5,000 less than the overall average of all employees’ annual salary. Since $10,000 is twice $5,000, this means the number of male employees is twice the number of female employees in the company. Therefore, choice D is the correct answer.

Alternate Solution:

If we were unable to determine that the number of males is twice the number of females, we can obtain the same result using algebra. Let m be the number of males and f be the number of females. Then, the sum of the salaries of the males is 65,000m, and the sum of the salaries of the females is 80,000f. The sum of the salaries of all the employees is 70,000(m + f); thus we have:

65,000m + 80,000f = 70,000(m + f)

65m + 80f = 70(m + f)

65m + 80f = 70m + 70f

10f = 5m

m = 2f

As we can see, the number of males is twice the number of females. The only answer choice where the number of males is twice the number of females is D.

Answer: D