pablovaldesvega wrote:
The average (arithmetic mean) of 11 numbers is 50. When the numbers are arranged in order from least to greatest, the average of the 6 smallest numbers is 44 and the average of the 6 greatest numbers is 57. What is the median of the 11 numbers?
A) 47
B) 50
C) 50.5
D) 53.5
E) 56
A = {\(x_1, \quad x_2,\quad ...\quad, x_5,\quad x_6,\quad x_7,\quad....\quad x_{10},\quad x_{11}\)}
The median of the set = \(x_6\)
The average (arithmetic mean) of 11 numbers is 50.\(x_1 +x_2+x_3+...x_{10}+x_{11} = 11*50 = 550\) --- (1)
...the average of the 6 smallest numbers is 44...\(x_1 +x_2+x_3+...x_{5}+x_{6} = 6*44\) --- (2)
...the average of the 6 greatest numbers is 57...\(x_6 +x_7+x_8+...x_{10}+x_{11} = 6*57\) --- (3)
Adding equations (2) and (3) we see that \(x_6\) has been added twice as the term is common both in equation (2) and equation (3)
\((x_1 +x_2+x_3+...x_{10}+x_{11}) + x_6 = 6*(44+57)\)
Substituting the value of (1)
\(550 + x_6 = 6*(44+57)\)
\( x_6 =606 - 550 = 56\)
Option E