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The average (arithmetic mean) of 4 positive integers is 50.

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iyersu
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The average (arithmetic mean) of 4 positive integers is 50. [#permalink] New post   Updated on: 21 Dec 2013, 05:05
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The average (arithmetic mean) of 4 positive integers is 50. If the average of 2 of these integers is 45, what is the greatest possible value that one of the other 2 integers can have?

A. 55
B. 65
C. 100
D. 109
E. 115
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D

Originally posted by iyersu on 21 Dec 2013, 04:31.
Last edited by Bunuel on 21 Dec 2013, 05:05, edited 1 time in total.
Renamed the topic and edited the question.
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Re: The average (arithmetic mean) of 4 positive integers is 50. [#permalink] New post   21 Dec 2013, 05:16
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iyersu wrote:
The average (arithmetic mean) of 4 positive integers is 50. If the average of 2 of these integers is 45, what is the greatest possible value that one of the other 2 integers can have?

A. 55
B. 65
C. 100
D. 109
E. 115


The sum of 4 integers is 4*50 = 200.
The sum of 2 integers is 2*45 = 90.

Thus, the sum of the other 2 integers is 200 - 90 = 110. Since we know that the integers are positive then the greatest one from these two can be 109, the other one being 1.

Answer: D.

Hope it's clear.
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Re: The average (arithmetic mean) of 4 positive integers is 50. [#permalink] New post   10 Sep 2014, 23:01
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iyersu wrote:
The average (arithmetic mean) of 4 positive integers is 50. If the average of 2 of these integers is 45, what is the greatest possible value that one of the other 2 integers can have?

A. 55
B. 65
C. 100
D. 109
E. 115


a + b + c + d = 200

a + b = 90

c + d = 110

Greatest possible = 109 (Just less than 1)

Answer = D
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Re: The average (arithmetic mean) of 4 positive integers is 50. [#permalink] New post   12 Dec 2016, 11:46
Sum(4)=200
Sum(2)=90
Hence um(2 leftovers)=200-90=110

Since there is no restriction of the median
Let one of them be 1 => other one will be 109

Hence D
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Re: The average (arithmetic mean) of 4 positive integers is 50. [#permalink] New post   30 Jan 2017, 16:31
Bunuel wrote:
iyersu wrote:
The average (arithmetic mean) of 4 positive integers is 50. If the average of 2 of these integers is 45, what is the greatest possible value that one of the other 2 integers can have?

A. 55
B. 65
C. 100
D. 109
E. 115


The sum of 4 integers is 4*50 = 200.
The sum of 2 integers is 2*45 = 90.

Thus, the sum of the other 2 integers is 200 - 90 = 110. Since we know that the integers are positive then the greatest one from these two can be 109, the other one being 1.

Answer: D.

Hope it's clear.


Sorry I do not understand why sum of two remaining integers = 110 becomes 109?
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Re: The average (arithmetic mean) of 4 positive integers is 50. [#permalink] New post   31 Jan 2017, 10:55
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kanusha wrote:
Bunuel wrote:
iyersu wrote:
The average (arithmetic mean) of 4 positive integers is 50. If the average of 2 of these integers is 45, what is the greatest possible value that one of the other 2 integers can have?

A. 55
B. 65
C. 100
D. 109
E. 115


The sum of 4 integers is 4*50 = 200.
The sum of 2 integers is 2*45 = 90.

Thus, the sum of the other 2 integers is 200 - 90 = 110. Since we know that the integers are positive then the greatest one from these two can be 109, the other one being 1.

Answer: D.

Hope it's clear.


Sorry I do not understand why sum of two remaining integers = 110 becomes 109?


x + y = 110, where both x and y are positive integers. The max value of say x there is 109, when y = 1.
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Re: The average (arithmetic mean) of 4 positive integers is 50. [#permalink] New post   20 Aug 2023, 12:38
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Re: The average (arithmetic mean) of 4 positive integers is 50. [#permalink]
20 Aug 2023, 12:38
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