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# The average (arithmetic mean) of x,x+2 ,x+4, and x+6 is 6. What is the

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Joined: 02 Sep 2009
Posts: 55802
The average (arithmetic mean) of x,x+2 ,x+4, and x+6 is 6. What is the  [#permalink]

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27 Nov 2018, 00:20
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Difficulty:

25% (medium)

Question Stats:

79% (01:47) correct 21% (01:41) wrong based on 63 sessions

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The average (arithmetic mean) of x, x + 2, x + 4, and x + 6 is 6. What is the average of x^2, (x + 2)^2, (x + 4)^2, and (x + 6)^2 ?

A. 30
B. 36
C. 41
D. 49
E. 52

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Re: The average (arithmetic mean) of x,x+2 ,x+4, and x+6 is 6. What is the  [#permalink]

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27 Nov 2018, 09:21
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Bunuel wrote:
The average (arithmetic mean) of x, x + 2, x + 4, and x + 6 is 6. What is the average of x^2, (x + 2)^2, (x + 4)^2, and (x + 6)^2 ?

A. 30
B. 36
C. 41
D. 49
E. 52

(x+ x + 2+ x + 4+ x + 6)= 6*4
x= 3

x^2, (x + 2)^2, (x + 4)^2, and (x + 6)^2

Substitute x = 3
we get
(9+25+49+81)/4= 164/4= 41 option C
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Re: The average (arithmetic mean) of x,x+2 ,x+4, and x+6 is 6. What is the  [#permalink]

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27 Nov 2018, 10:01
Bunuel wrote:
The average (arithmetic mean) of x, x + 2, x + 4, and x + 6 is 6. What is the average of x^2, (x + 2)^2, (x + 4)^2, and (x + 6)^2 ?

A. 30
B. 36
C. 41
D. 49
E. 52

$$\frac{(4x+12)}{4} =6$$

$$4x+12=24$$

$$4x = 12$$

$$x=3$$

$$\frac{3^2 +(3 + 2)^2 +(3+ 4)^2 +(3 + 6)^2}{4} = 41$$
Re: The average (arithmetic mean) of x,x+2 ,x+4, and x+6 is 6. What is the   [#permalink] 27 Nov 2018, 10:01
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# The average (arithmetic mean) of x,x+2 ,x+4, and x+6 is 6. What is the

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