The diagonally opposite corners of a square have coordinates of (–1,2)

Find the mid-point of the line AB in the above figure.
Let C be the mid-point as mentioned in the above diagram.

\(C(x,y) = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\)

\(C(x,y)=(\frac{-1+5}{2},\frac{2+2}{2})=(\frac{4}{2},\frac{4}{2})=(2,2)\)

Distance between \(CD=AC=CB=CE=3\) (From my pervious post)

Now add/subtract \(3\) from the mid-point to get the coordinates of the other diagonals.

\(D(x,y)=(2,2+3)=(2,5)\) Only the y-axis changes and the x-axis remains the same.
\(E(x,y)=(2,2-3)=(2,-1)\) Only the y-axis changes and the x-axis remains the same.

Hope this clarifies. Do let me know if you need any further clarification.

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