kannn wrote:

The equation of line n is y = 4/3*x - 100. What is the smallest possible distance in the xy-plane from the point with coordinates (0, 0) to any point on line n?

A. 48

B. 50

C. 60

D. 75

E. 100

The answer is C as follows.

Given the line y = 4/3*x - 100 ==> 4x-3y-300=0

As per the formula distance of a point (x1,y1) from line ax+by+c=0 is |ax1+by1+c|/\sqrt{(\((a^2)\)+\((b^2)\))}

Putting the value in the formula |a*0+b*0-300|/\sqrt{(\(4^2\)+\(3^2\))} ==> \(\frac{300}{5}\) ==>60

Hence answer is C

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