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The equation of line n is y = 4/3*x - 100. What is the small

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Joined: 08 Oct 2013
Posts: 51
Re: The equation of line n is y = 4/3*x - 100. What is the small [#permalink]

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New post 14 May 2015, 08:36
kannn wrote:
The equation of line n is y = 4/3*x - 100. What is the smallest possible distance in the xy-plane from the point with coordinates (0, 0) to any point on line n?

A. 48
B. 50
C. 60
D. 75
E. 100


Don't know if remembering formulas are your thing but the Distance between a point (x1, y1) and line ax + by + c = 0 is given by the formula lax1 + by1 + cl / Sqrt (a^2 + b^2)

y = 4/3*x - 100 is 4x-3y-300=0

Substituting in the formal, will give you distance as 60.

The formula approach will take about just under a minute...

Regards,
Aj
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The equation of line n is y = 4/3*x - 100. What is the small [#permalink]

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New post 30 Sep 2017, 09:58
kannn wrote:
The equation of line n is y = 4/3*x - 100. What is the smallest possible distance in the xy-plane from the point with coordinates (0, 0) to any point on line n?

A. 48
B. 50
C. 60
D. 75
E. 100


The answer is C as follows.

Given the line y = 4/3*x - 100 ==> 4x-3y-300=0
As per the formula distance of a point (x1,y1) from line ax+by+c=0 is |ax1+by1+c|/\sqrt{(\((a^2)\)+\((b^2)\))}

Putting the value in the formula |a*0+b*0-300|/\sqrt{(\(4^2\)+\(3^2\))} ==> \(\frac{300}{5}\) ==>60

Hence answer is C
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Re: The equation of line n is y = 4/3*x - 100. What is the small [#permalink]

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New post 30 Sep 2017, 13:32
kannn wrote:
The equation of line n is y = 4/3*x - 100. What is the smallest possible distance in the xy-plane from the point with coordinates (0, 0) to any point on line n?

A. 48
B. 50
C. 60
D. 75
E. 100


3:4:5 right triangle=60:80:100
60
C
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Re: The equation of line n is y = 4/3*x - 100. What is the small   [#permalink] 30 Sep 2017, 13:32

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