Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Does GMAT RC seem like an uphill battle? e-GMAT is conducting a free webinar to help you learn reading strategies that can enable you to solve 700+ level RC questions with at least 90% accuracy in less than 10 days. Sat., Oct 19th at 7 am PDT
The figure above represents a semicircular archway over a flat street.
[#permalink]
Show Tags
22 Jun 2018, 00:30
22
00:00
A
B
C
D
E
Difficulty:
5% (low)
Question Stats:
91% (01:33) correct 9% (01:53) wrong based on 761 sessions
HideShow timer Statistics
The figure above represents a semicircular archway over a flat street. The semicircle has a center at O and a radius of 6 feet. What is the height h, in feet, of the archway 2 feet from its center?
Re: The figure above represents a semicircular archway over a flat street.
[#permalink]
Show Tags
23 Jun 2018, 09:52
3
Top Contributor
Bunuel wrote:
The figure above represents a semicircular archway over a flat street. The semicircle has a center at O and a radius of 6 feet. What is the height h, in feet, of the archway 2 feet from its center?
Let's add the radius of 6 feet to the diagram to get:
From here, we can see the right triangle hiding within the diagram, which means we can apply the Pythagorean Theorem. Se can write: h² + 2² = 6² Simplify: h² + 4 = 36 So, we get: h² = 32 This means h = √32 Check the answer choices. . . √32 is not among them. Looks like we need to simplify √32
We'll use the fact that √(xy) = (√x)(√y) So, √32 = √[(16)(2)] = (√16)(√2) = (4)(√2) = 4√2 Check the answer choices. . . D
Re: The figure above represents a semicircular archway over a flat street.
[#permalink]
Show Tags
25 Jun 2018, 12:06
2
Bunuel wrote:
The figure above represents a semicircular archway over a flat street. The semicircle has a center at O and a radius of 6 feet. What is the height h, in feet, of the archway 2 feet from its center?
A. √2
B. 2
C. 3
D. 4√2
E. 6
Since the radius is 6 feet, we can create a right triangle with hypotenuse of 6, leg of 2, and leg of h; thus, we have:
Re: The figure above represents a semicircular archway over a flat street.
[#permalink]
Show Tags
02 Aug 2018, 13:30
if the radius is 6 max height of the arch can be 6 from the center of semi-circle. So height asked in question which is two feet away from center is definitely less than 6 . Also point 2 feet away from center to end of semicircle the dist is 4 so height is little more than 4 . So the only answer choice that matches it is D
_________________
Probus
~You Just Can't beat the person who never gives up~ Babe Ruth
Re: The figure above represents a semicircular archway over a flat street.
[#permalink]
Show Tags
23 Sep 2019, 05:19
Hello from the GMAT Club BumpBot!
Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________