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The HCF of two numbers is 21 and their LCM is 4641. If one of the n

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New post 23 Aug 2019, 10:39
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The HCF of two numbers is 21 and their LCM is 4641. If one of the numbers is between 200 and 300, find the other number.

A. 221

B. 273

C. 357

D. 441

E. 289
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Re: The HCF of two numbers is 21 and their LCM is 4641. If one of the n  [#permalink]

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New post 23 Aug 2019, 12:36
1
HCF{a, b}= 21
a=21x
b=21y

Also LCM{a, b}=4641
hence x*y=4641/21= 221

Given that 200<21x<300 or 9.efg<x<14.jkl
x can be 10, 11, 12, 13 or 14
only 13 is the factor of 221

a=21*13=273
b=21*(221/13)=21*17=357

C



AbdulMalikVT wrote:
The HCF of two numbers is 21 and their LCM is 4641. If one of the numbers is between 200 and 300, find the other number.

A. 221

B. 273

C. 357

D. 441

E. 289
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Joined: 06 Mar 2018
Posts: 2
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Re: The HCF of two numbers is 21 and their LCM is 4641. If one of the n  [#permalink]

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New post 23 Aug 2019, 23:59
Why can't the numbers be 221 and 441 instead? Could someone please help me I am confused.
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Re: The HCF of two numbers is 21 and their LCM is 4641. If one of the n  [#permalink]

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New post 04 Sep 2019, 03:17
SShawarma wrote:
Why can't the numbers be 221 and 441 instead? Could someone please help me I am confused.



Can you show how did you solve to get these two nos. 221 and 441?

The H.C.F. of 221 and 441 is not 21.
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Re: The HCF of two numbers is 21 and their LCM is 4641. If one of the n   [#permalink] 04 Sep 2019, 03:17
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