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09 Nov 2017, 00:38
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B
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79% (00:43) correct
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The probability that an event A occurs is 1/2 and the probability that an even B occurs is 1/3. If event A and event B are independent, what is the probability that event A occurs but event B does not occur?
A. 1/6
B. 1/3
C. 1/2
D. 2/3
E. 5/6
A. 1/6
B. 1/3
C. 1/2
D. 2/3
E. 5/6
09 Nov 2017, 01:00
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Since events A and B are independent, P(A∩B) = P(A) ∙P(B).
The probability P(A-B) = P(A) - P(A∩B) = P(A) - P(A) ∙P(B) = 1/2 – (1/2)(1/3) = 1/2 – 1/6 = 2/6 = 1/3.
Thus, the answer is B.
Answer: B
Since events A and B are independent, P(A∩B) = P(A) ∙P(B).
The probability P(A-B) = P(A) - P(A∩B) = P(A) - P(A) ∙P(B) = 1/2 – (1/2)(1/3) = 1/2 – 1/6 = 2/6 = 1/3.
Thus, the answer is B.
Answer: B
12 Nov 2017, 08:47
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MathRevolution
The probability that event B does not occur is 1 - 1/3 = 2/3.
Since we want the probability that A occurs AND that B does not occur, we multiply their respective probabilities. Thus, the probability that event A occurs but event B does not occur is 1/2 x 2/3 = 1/3.
Answer: B
