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The sum of the interior angles of any polygon with n sides is 180(n -

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Re: The sum of the interior angles of any polygon with n sides is 180(n - [#permalink]
By definition, a quadrilateral has 4 sides and the sum of interior angles is 360.

From the question stem, we have been told that the sum of the interior angles of
the polygon is thrice the sum of the interior angles of the polygon($$3*360 = 1080$$)

Solving for n, we get $$180(n - 2) = 1080$$ -> $$n - 2 = \frac{1080}{180} = 6$$ -> $$n = 8$$

Therefore, Polygon P has 8(Option B) sides whose interior angles sum thrice that of a quadrilateral.
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Re: The sum of the interior angles of any polygon with n sides is 180(n - [#permalink]
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Re: The sum of the interior angles of any polygon with n sides is 180(n - [#permalink]
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