Re: The total weight of all residents of Ranchville
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14 Jan 2014, 07:17
The total weight of all residents of Ranchville is the same as the total weight of all residents of Crashville. Are there more residents in Ranchville than in Crashville?
(1) The range of weights of residents of Ranchville is more than the range of weights of residents of Crashville.
If R={100, 200} (2 residents weighing 100 and 200 kg) and S={100, 100, 100} (3 residents weighing 100 kg each), then there are less residents in R than in C.
If R={100, 200} (2 residents weighing 100 and 200 kg) and S={300} (1 resident weighing 300 kg), then there are more residents in R than in C.
Not sufficient.
(2) The mean weight of residents of Ranchville is more than the mean weight of residents of Crashville --> (average weight)=(total weight)/(number of residents).
Thus we are told that (total weight of R)/(number of residents in R) > (total weight of C)/(number of residents in C). Since we are told that the total weight of all residents in R and S are the same, then we have that 1/(number of residents in R) > 1/(number of residents in C) --> (number of residents in C) > (number of residents in R). Sufficient.
Answer: B.