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01 Jan 2008, 18:27
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The weight of every type A widget is the same, the weight of every type B widget is the same, and the weight of every type C widget is the same. If the weight of 8 type A widgets is equal to the weight of 3 type B widgets, and the weight of 5 type B widgets is equal to the weight of 7 type C widgets. What is the ratio of the total weight of 1 type A widget and 1 type B widget, to the total weight of 1 type B widget and 1 type C widget?
12/23
21/40
2/3
77/96
10/7
Please explain.
[spoiler]OA is D[/spoiler]
12/23
21/40
2/3
77/96
10/7
Please explain.
[spoiler]OA is D[/spoiler]
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02 Jan 2008, 02:35
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D
8A=3B; 5B=7C; r=(A+B)/(B+C) ?
B=8/3A; C=5/7B=5/7*8/3A
r=(A+B)/(B+C)=(A+8/3A)/(8/3A+5/7*8/3A)=(11/3)/(8/3*12/7)=77/96
8A=3B; 5B=7C; r=(A+B)/(B+C) ?
B=8/3A; C=5/7B=5/7*8/3A
r=(A+B)/(B+C)=(A+8/3A)/(8/3A+5/7*8/3A)=(11/3)/(8/3*12/7)=77/96
02 Jan 2008, 06:02
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AVakil
8A=3B AND 5B=3C...let's put everything in terms of B, so ... A=3/8*B and C=5/7*B, thus (A+B)/B+C=11/8*7/12=77/96. OA must be D
