Hi Bunuel, can you please check if the answer options are correct.


Let the volume of each container = V

When the contents of the 3 containers are put together, total Volume = 3V

Total Water = Water from 1 + Water from 2 + Water from 3

= \(\frac{5}{9}*V + \frac{3}{11}*V + \frac{1}{12}*V = \frac{361}{396}*V\)

Then \(\frac{Percentage}{100} * Total = Portion\)

%\( = \frac{\frac{361}{396}*V}{3V} * 100 = 30.39\)


Arun Kumar
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I think the choices are correct. You should add the water percentage of each other : 5+3+1 = 9 and the total mix is 32. 9/32 x 100 = 28.125 The answer is C

Solution:

We could let the capacity of each identical vessel be 396 liters. The number 396 is the least common multiple of 9, 11 and 12 where each of these numbers is the sum of the numbers in each of the three ratios, respectively.

Now, let the first vessel contain x liters of fruit juice, 3x liters of soda and 5x liters of water. We have:

x + 3x + 5x = 396

9x = 396

x = 44

So there are 5(44) = 220 liters of water in the first vessel.

Let the second vessel contain 6y liters of fruit juice, 2y liters of soda and 3y liters of water. We have:

6y + 2y + 3y = 396

11y = 396

y = 36

So there are 3(36) = 108 liters of water in the second vessel.

Let the third vessel contain 7z liters of fruit juice, 4z liters of soda and z liters of water. We have:

7z + 4z + 1z = 396

12z = 396

z = 33

So there are 33 liters of water in the third vessel.

When the contents of all the three vessels are poured into an empty container, the container now has a total of 396 x 3 = 1188 liters of content, of which 220 + 108 + 33 = 361 liters are water. Therefore, water constitutes 361/1188 ≈ 30.4% of the contents in the container.

Answer: 30.4%
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