Last visit was: 26 Apr 2026, 08:00 It is currently 26 Apr 2026, 08:00
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
arjtryarjtry
User avatar
Current Student
Joined: 11 May 2008
Last visit: 18 Sep 2010
Posts: 376
Own Kudos:
Concentration: General
Posts: 376
Kudos: 1,344
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
x2suresh
Joined: 07 Nov 2007
Last visit: 18 Aug 2012
Posts: 711
Own Kudos:
Given Kudos: 5
Location: New York
Posts: 711
Kudos: 3,148
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
arjtryarjtry
User avatar
Current Student
Joined: 11 May 2008
Last visit: 18 Sep 2010
Posts: 376
Own Kudos:
Concentration: General
Posts: 376
Kudos: 1,344
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
scthakur
Joined: 17 Jun 2008
Last visit: 30 Jul 2009
Posts: 608
Own Kudos:
Posts: 608
Kudos: 453
Kudos
Add Kudos
Bookmarks
Bookmark this Post
arjtryarjtry
x2suresh
arjtryarjtry
throw some light on the meaning...

say -x=y (positive)

\(sqrt(y|-y|)= sqrt(y^2)=y=-x\)

sqrt(y^2)=+/-y . why have u not considered -y?

-y is not possible as y is negative.
User avatar
Twoone
Joined: 02 Sep 2008
Last visit: 25 Oct 2008
Posts: 17
Posts: 17
Kudos: 0
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Suresh,

I go with your explanation,

i agree till y = -x

but I think answer should be x.

as x < 0 so - ( -x ) = x.

Please give some points on this.



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!