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Re: M05-27 [#permalink]
Bunuel wrote:
Official Solution:

Carly has three movies that she can watch during the weekend: an action movie, a comedy, or a drama. However, she wants to watch the same drama movie three times, an action movie once and a comedy movie also once. In how many different ways can she arrange these five screenings?

A. 6
B. 20
C. 24
D. 60
E. 120


The number of different ways Carly can watch Drama, Drama, Drama, Action, Comedy (DDDAC) is basically the number of arrangements of 5 letters DDDAC out of which 3 D's are identical, so it's \(\frac{5!}{3!}=20\).


Answer: B


Hi Bunuel,

The above explanation is perfect. Thank you.
However, if the question asks with respect to DDDAC, how many ways that 3Ds are NOT Together then how exactly should one approach?

I think: Total ways possible - when the 3Ds are together.
ie. 5!/3! - ?
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Re: M05-27 [#permalink]
What is the rule for this type of combination problem? It doesn't seem to follow the fundamental counting rule (n!)/[(r!)(n-r)!].... or does it?
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Re: M05-27 [#permalink]
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patrickmhoy wrote:
What is the rule for this type of combination problem? It doesn't seem to follow the fundamental counting rule (n!)/[(r!)(n-r)!].... or does it?


The first thing in Combinatorics is to figure out whether the problem is of Permutation or Combination.

This problem asks for the "arrangement", so this is clearly a Permutation problem. But the author also says that one type of movie (Drama) has to be watched thrice.

So possible arrangements are -

DDDAC
ADDDC
ACDDD
DDACD
...
..
and so on.

Now you should see here that the 3 Ds are same, so their arrangement, when they are placed together, doesn't really matter.

So, like Bunuel has mentioned in the official solution, the total number of arrangements for n objects with repetition, in which object-1 repeats n1 times, object-2 repeats n2 times, object-3 repeats n3 times and so on, can be given from the formula -
n!/(n1! *n2! * n3! .....)
= 5!/(3! * 1! * 1*)
= 5!/3!
= 20
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Re: M05-27 [#permalink]
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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M05-27 [#permalink]
 
Bunuel wrote:
Carly has three different movies to watch during the weekend: an action movie, a comedy movie, and a drama movie. She plans to watch the drama movie three times, the action movie once, and the comedy movie once, for a total of five screenings. How many different ways can she arrange the order of these five movie screenings?

A. 6
B. 20
C. 24
D. 60
E. 120

­Hey Bunuel,

Wanted to know that because it is not mentioned that Drama movies are distinct i.e. why we are doing \( \frac{ 5!}{3! } \)  ?

If they had mentioned Distinct then solution would be 5! = 120 . Correct ?


Just wanted to know in general that if Gmat does not mentions in these type of Questions Distinct then, we would have to assume objects to be Identical . Like in this question . Correct ?­
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Re: M05-27 [#permalink]
Expert Reply
 
Gangadhar111990 wrote:
Bunuel wrote:
Carly has three different movies to watch during the weekend: an action movie, a comedy movie, and a drama movie. She plans to watch the drama movie three times, the action movie once, and the comedy movie once, for a total of five screenings. How many different ways can she arrange the order of these five movie screenings?

A. 6
B. 20
C. 24
D. 60
E. 120

­Hey Bunuel,

Wanted to know that because it is not mentioned that Drama movies are distinct i.e. why we are doing \( \frac{ 5!}{3! } \)  ?

If they had mentioned Distinct then solution would be 5! = 120 . Correct ?


Just wanted to know in general that if Gmat does not mentions in these type of Questions Distinct then, we would have to assume objects to be Identical . Like in this question . Correct ?­

­

The question says that there are THREE DIFFERENT movies: an action movie, a comedy movie, and a drama movie. Carly plans to watch THE drama movie three times, THE action movie once, and THE comedy movie once, for a total of five screenings. 

I think it's clear that Carly wants to watch the three movies mentioned in the setup of the question. So, THE drama movie three times, THE action movie once, and THE comedy movie once, for a total of five screenings.

GMAT questions are always precise, so by reading them correctly, you'll know whether the objects mentioned are distinct or not.

P.S. If the question simply were in how many ways one can watch 5 different movies, then the answer would be 5!­
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