Forget the conventional way to solve DS questions.
We will solve this DS question using the variable approach.DS question with 2 variables and 1 Equation: Let the original condition in a DS question contain 2 variables and 1 Equation. Now, 2 variables and 1 Equation would generally require 1 more equation for us to be able to solve for the value of the variable.
We know that each condition would usually give us an equation, and Since we need 1 more equations to match the numbers of variables and equations in the original condition, the logical answer is D.
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Let’s apply the 3 steps suggested previously. [Watch lessons on our website to master these 3 steps]
Step 1 of the Variable Approach: Modifying and rechecking the original condition and the question.We have to find Is it true that a > b. => a > b
OR a - b > 0
Second and the third step of Variable Approach: From the original condition, we have 2 variables (a and b) and 1 Equation(a - b > 0). To match the number of variables with the number of equations, we need 1 more equation. Since conditions (1) and (2) will provide 1 equation each, D would most likely be the answer.Let’s take a look at each conditions .Condition(1) tells us that the 2a > 2b = .=> 2a > 2b = a > b => a - b> 0 - YES
Since the answer is unique YES , condition(1) is sufficient by CMT 1.Condition(2) tells us that a + c > b + c.=> a + c > b + c => a > b => a - b > 0
Since the answer is unique YES , condition(2) is sufficient by CMT 1. Each condition alone is sufficient.So, D is the correct answer.Answer: D