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Re: 2+1/(2+2)+1/(22) = [#permalink]
 
Danou wrote:
\(\sqrt{2} +\frac{1}{2 + \sqrt{2}} + \frac{1}{\sqrt{2} - 2} = \)

A. \(0\)

B. \(2\)

C. \(\frac{\sqrt{2}}{2}\)

D. \(\sqrt{2}\)

E. \(2\sqrt{2}\)




 

\(\frac{1}{2 + \sqrt{2}} + \frac{1}{\sqrt{2} - 2}\)

\(\frac{\sqrt{2} - 2 + 2 + \sqrt{2}}{(2 + \sqrt{2})(\sqrt{2} - 2)}\)­

\(\frac{2\sqrt{2}}{2-4}\)­

\(\frac{-2\sqrt{2}}{2}\)­

\(-\sqrt{2}\)­

\(\sqrt{2} +\frac{1}{2 + \sqrt{2}} + \frac{1}{\sqrt{2} - 2} = \)

\(\sqrt{2} -\sqrt{2}\)

= 0

Option A

 ­
GMAT Club Bot
Re: 2+1/(2+2)+1/(22) = [#permalink]
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