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Re: If Jake loses 8 pounds, he will weigh twice as much as his [#permalink]
sportypk wrote:
If Jake loses 8 pounds, he will weigh twice as much as his
sister. Together they now weigh 278 pounds. What is Jake’s
present weight, in pounds?
(A) 131
(B) 135
(C) 139
(D) 147
(E) 188

the OA is 188...could anyone explain how?


My solution is:
(278-8)/3 = 90
90*2+8= 188
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Re: If Jake loses 8 pounds, he will weigh twice as much as his [#permalink]
Expert Reply
sportypk wrote:
If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake’s present weight, in pounds?

(A) 131
(B) 135
(C) 139
(D) 147
(E) 188


Let J be Jake's present weight and S be his sister's weight, then we can construct two linear equations:
J=2S+8;
J+S=278.

Subtract one from another: S=278-2S-8 --> S=90 --> J=188.

Answer: E.

OPEN DISCUSSION OF THIS QUESTION IS HERE: https://gmatclub.com/forum/if-jake-lose ... 43752.html
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Re: If Jake loses 8 pounds, he will weigh twice as much as his [#permalink]
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