Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 02 Dec 2012
Posts: 172

If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
07 Dec 2012, 04:08
Question Stats:
94% (01:36) correct 6% (01:59) wrong based on 1852 sessions
HideShow timer Statistics
If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake's present weight, in pounds? (A) 131 (B) 135 (C) 139 (D) 147 (E) 188
Official Answer and Stats are available only to registered users. Register/ Login.




Target Test Prep Representative
Status: Head GMAT Instructor
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2800

Re: If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
28 Apr 2016, 06:22
Walkabout wrote: If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake's present weight, in pounds?
(A) 131 (B) 135 (C) 139 (D) 147 (E) 188 This problem can be solved as a simple word problem in which we must convert words to math. Before we create our equations, we want to define some variables. J = Jake’s current weight, in pounds S = Sister’s current weight, in pounds We are told that “If Jake loses 8 pounds, he will weigh twice as much as his sister." We put this into an equation: J – 8 = 2S We can isolate J by adding 8 to 2S: J = 2S + 8 (Equation 1) Next, we are told that “Together they now weigh 278 pounds.” We can also put this into an equation. J + S = 278 (Equation 2) To solve this equation, we can substitute 2S + 8 from Equation 1 for the variable J in Equation 2: 2S + 8 + S = 278 3S = 270 S = 90 We now know that the sister weighs S = 90 pounds, and we can plug that value into either equation to determine J. Let’s plug 90 for S into equation 2: J + 90 = 278 J = 188 Answer: E
_________________
5star rated online GMAT quant self study course See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews
If you find one of my posts helpful, please take a moment to click on the "Kudos" button.




Math Expert
Joined: 02 Sep 2009
Posts: 64090

Re: If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
07 Dec 2012, 04:12
Walkabout wrote: If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake's present weight, in pounds?
(A) 131 (B) 135 (C) 139 (D) 147 (E) 188 Let J be Jake's present weight and S be his sister's weight, then we can construct two linear equations: J=2S+8; J+S=278. Subtract one from another: S=2782S8 > S=90 > J=188. Answer: E.
_________________



Manager
Joined: 07 Apr 2014
Posts: 95

Re: If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
11 Sep 2014, 06:10
Walkabout wrote: If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake's present weight, in pounds?
(A) 131 (B) 135 (C) 139 (D) 147 (E) 188 (x8) = 2s s+x = 278 > s= 278x x8 = 2(278x) 3x=564 x=188



SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1709
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)

Re: If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
24 Sep 2014, 18:44
..................... Jack ......................... Sister
Now ................ x ................................. y
8 yrs before....... (x8)
2y = x  8
x = 2y+8
Given that 2y + 8 + y = 270
y = 90
x = 188
Answer = E



EMPOWERgmat Instructor
Status: GMAT Assassin/CoFounder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 16711
Location: United States (CA)

If Jake loses 8 pounds, he will weigh twice as much as his siste
[#permalink]
Show Tags
04 Jan 2015, 11:55
Hi All, This question can be solved with fairly straightforward Algebra (as the other solutions have proven). It can also be solved by TESTing THE ANSWERS and a bit of logic. We're told that the total weight of Jake and his sister is 278 pounds. We're also told that if Jake lost 8 pounds, then he would weight TWICE as much as his sister. This means that, right now, Jake weighs MORE than TWICE his sister. We're asked for Jake's current weight. Since Jake weighs more than twice his sister, his weight is MORE than 2/3 of the 278 pounds. Looking at these answer choices, I would TEST one of the bigger values first... Under normal circumstances, that would be Answer D. With a quick estimate though we can see that 2/3 of 270 pounds would be 180 pounds, but Jake has to weight MORE than that, so I'm going to TEST Answer E first.... If Jake weights 188 pounds... Jake  8 = 180 pounds.... Sister = 90 pounds 90 + 180 + 8 = 278 pounds This is a MATCH for the information in the prompt, so Jake MUST weight 188 pounds. Final Answer: GMAT assassins aren't born, they're made, Rich
_________________
Contact Rich at: Rich.C@empowergmat.comThe Course Used By GMAT Club Moderators To Earn 750+ souvik101990 Score: 760 Q50 V42 ★★★★★ ENGRTOMBA2018 Score: 750 Q49 V44 ★★★★★



Intern
Joined: 24 May 2016
Posts: 17
Location: Germany
Concentration: International Business, General Management

If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
04 Jun 2017, 00:25
You can also test the answers. When you realize that when you choose 188 for Jake's weight you get from the equations, a nice round number for his sister age and the work involved is fast: J8=2S, where J stands for Jake and S for his sister > 1888=2S > S=90. Now you can plug in the obtained value in the second equation: J+S= 278 > As we have chosen 188 for Jake and got 90 pounds for his sister> 188+90=278. This is a match. Option E is the correct answer.



Manager
Joined: 07 Jun 2017
Posts: 158
Location: India
Concentration: Technology, General Management
GPA: 3.6
WE: Information Technology (Computer Software)

Re: If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
21 Sep 2017, 00:06
let Jack's Weight be J His sister weight be S J8 = 2S 1 J+S = 278 2 Then, J= 2S+8 2S+8+S = 278 S= 270/3 S=90 then J = 188 Answer is E



Intern
Joined: 01 May 2017
Posts: 33

If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
16 Nov 2017, 05:41
One of my favorite method to attempt questions is by using as low level an approach as possible:
 On this question we know that 278 is the current sum of Jake's and his sister weights
 We also know that 270 is the sum of their weights if Jake loses 8 pounds
 Since 270 equals 2 parts from Jake's weight and 1 part from his sister weight so we can have following ratio
 Jake: 2 parts of 270 (180) and Sister: 1 part of 270 (90)
 So Jake's current weight will be those 2 parts (180) plus the weight that he has not lost yet (8) = 188 (option E)  In fact we don't even need to calculate 188. Since we know that Jake's weight is at least 180 and since none of the other options is anywhere close to 180, so our answer is automatically option  E. Moreover, if you are pressed for time then you don't even have to consider 8. You can use the approximation technique to divide 278 into 3 equal parts which will be about ~93 and so Jake's weight is approximately 186 (and so only option E works)



GMAT Club Legend
Joined: 11 Sep 2015
Posts: 4871
Location: Canada

Re: If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
17 Jan 2019, 05:42
Walkabout wrote: If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake's present weight, in pounds?
(A) 131 (B) 135 (C) 139 (D) 147 (E) 188 Here's a solution that uses one variable. Let x = Jake's present weight in pounds So, x  8 = Jake's hypothetical weight IF he were to lose 8 pounds If Jake loses 8 pounds, he will weigh twice as much as his sister. In other words, the sister weighs HALF as much as Jake's hypothetical weight of x  8 pounds So, (x  8)/2 = sister's present weight Together they NOW weigh 278 pounds. So, Jake's present weight + sister's present weight = 278 So, x + (x  8)/2 = 278 Eliminate the fraction by multiplying both sides by 2 to get: 2x + (x  8) = 556 Simplify: 3x  8 = 556 Add 8 to both sides: 3x = 564 Solve: x = 564/3 = 188 Answer: E Cheers, Brent
_________________
Test confidently with gmatprepnow.com



GMATH Teacher
Status: GMATH founder
Joined: 12 Oct 2010
Posts: 937

Re: If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
17 Jan 2019, 08:44
Walkabout wrote: If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake's present weight, in pounds?
(A) 131 (B) 135 (C) 139 (D) 147 (E) 188
\(? = 2M\) \(\left\{ \matrix{ \,2M  8 = 2S \hfill \cr \,2M + S = 278 \hfill \cr} \right.\,\,\,\,\, \cong \,\,\,\,\left\{ \matrix{ \,M  S = 4 \hfill \cr \,2M + S = 278 \hfill \cr} \right.\,\,\,\,\,\,\mathop \Rightarrow \limits^{\left( + \right)} \,\,\,\,\,\left( {{2 \over 3}} \right)3M = \left( {{2 \over 3}} \right)\left( {270 + 12} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\,? = 2M = 2 \cdot 94 = 188\) We follow the notations and rationale taught in the GMATH method. Regards, Fabio.
_________________
Fabio Skilnik :: GMATH method creator (Math for the GMAT) Our highlevel "quant" preparation starts here: https://gmath.net



Manager
Joined: 09 Mar 2018
Posts: 55
Location: India

Re: If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
13 May 2019, 23:46
I loved it how FANewJersey has put this question in, option E is indeed pretty far from others and if hard pressed on time such a trick can indeed be really handy



Intern
Joined: 27 Oct 2018
Posts: 2

Re: If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
24 Jun 2019, 17:18
Walkabout wrote: If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake's present weight, in pounds?
(A) 131 (B) 135 (C) 139 (D) 147 (E) 188 All you need to do for this one is find out the first equation and start plugging in answer choices. So: J8=2(S) A  123 = 2(S) B  127 = 2(S) C  131 = 2(S) D  149 = 2(S) E  180 = 2(S) If you were to go on to find what S=, you will notice only one is even (E). Because the weight together is an integer, you can stop here and grab E as the final answer.



VP
Joined: 18 Dec 2017
Posts: 1360
Location: United States (KS)
GMAT 1: 600 Q46 V27

Re: If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
29 Oct 2019, 16:58
Walkabout wrote: If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake's present weight, in pounds?
(A) 131 (B) 135 (C) 139 (D) 147 (E) 188 Even8=Even Even+2*Even= 278 (Even) Well, we need an Even. Only E.
_________________
The Moment You Think About Giving Up, Think Of The Reason Why You Held On So Long Why You Don’t Deserve A 700 On Your GMAT
Learn from the Legend himself: All GMAT Ninja LIVE YouTube videos by topicYou are missing on great learning if you don't know what this is: Project SC Butler



SVP
Joined: 23 Feb 2015
Posts: 1870

If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
14 Apr 2020, 05:13
Quote: If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake's present weight, in pounds?
(A) 131 (B) 135 (C) 139 (D) 147 (E) 188 Hello Experts, EMPOWERgmatRichC, VeritasKarishma, IanStewartIs it the right way...? Let Jake's weight is 11 (odd number). After losing 8 pounds, his new weight would be 3. This 3 pounds is the twice of his sister. So, his sister's weight is \(\frac{3}{2}=1.5\) pound. Their present weight is 11+1.5 pounds=12.5 pounds (this is fraction value). The question prompt gave their total weight is EVEN (278). So, Jake's weight can't be odd (say 11). The weight of Jake must be EVEN. In the answer option, every answer option is ODD without choice E. So, choice E is the correct choice. Or, We can cross out choices A, B and C easily. A, B and C:Half of 278 is 139, which is choice C. Jake's weight has to be a lot more than half of 278. Because, together they weigh 278, but Jake is more than twice as much as his sister. So, he needs to be a lot more than half of 278. The correct choice MUST be greater than 139. Thanks__



EMPOWERgmat Instructor
Status: GMAT Assassin/CoFounder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 16711
Location: United States (CA)

Re: If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
Show Tags
07 May 2020, 14:22
Hi Asad, YES  the Number Properties that you've described could be used to correctly answer this question. This goes to show how important it is to pay attention to how the answers are written. There are plenty of circumstances (in BOTH the Quant and Verbal sections), in which you can use the 5 answer choices "against" the prompt to logically eliminate the wrong answers and zeroin on the correct one. GMAT assassins aren't born, they're made, Rich
_________________
Contact Rich at: Rich.C@empowergmat.comThe Course Used By GMAT Club Moderators To Earn 750+ souvik101990 Score: 760 Q50 V42 ★★★★★ ENGRTOMBA2018 Score: 750 Q49 V44 ★★★★★




Re: If Jake loses 8 pounds, he will weigh twice as much as his
[#permalink]
07 May 2020, 14:22




