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# Vertices of a triangle have coordinates (-1, 0),(4, 0) ,and

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Current Student
Joined: 11 May 2008
Posts: 551
Vertices of a triangle have coordinates (-1, 0),(4, 0) ,and [#permalink]

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28 Aug 2008, 20:26
Vertices of a triangle have coordinates (-1, 0),(4, 0) ,and (0, A) . Is the area of the triangle bigger than 15 ?

1. A < 3
2. The triangle is right

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Joined: 07 Nov 2007
Posts: 1738
Location: New York
Re: nice one.... [#permalink]

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28 Aug 2008, 20:54
arjtryarjtry wrote:
Vertices of a triangle have coordinates (-1, 0),(4, 0) ,and (0, A) . Is the area of the triangle bigger than 15 ?

1. A < 3
2. The triangle is right

distinance between (-1, 0),(4, 0) =5
this is base of the triangle..

distance between (0,0) and other vertex (0,A) = A (height of the triangle..

A<3 e.g A=2 area <15
A=-5 area >25

insuffcient
2)
(-1,0)(4,0) (0,A) form right angle

distinace between (-1,0)(4,0) = hypotenuse

$$1^2+A^2+4^2+A^2 = 5^2$$
SOLVE A= +2 OR -2

area <15
suffcient

B
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Intern
Joined: 04 Aug 2008
Posts: 11
Re: nice one.... [#permalink]

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29 Aug 2008, 03:39
Suresh answer is right... but A value would be either +3 or -3
Senior Manager
Joined: 09 Oct 2007
Posts: 456
Re: nice one.... [#permalink]

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29 Aug 2008, 08:58
Statement 1 only says A < 3.

I agree on B:

From the stem: (5A)/2>15 ==> A>6?
1) INSUFF.
2) Since it's a right triangle, no side will be larger than the hypotenuse. Thus, A<5. SUFF.
Manager
Joined: 03 Jun 2008
Posts: 128
Schools: ISB, Tuck, Michigan (Ross), Darden, MBS
Re: nice one.... [#permalink]

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07 Sep 2008, 01:27
x2suresh wrote:
arjtryarjtry wrote:
Vertices of a triangle have coordinates (-1, 0),(4, 0) ,and (0, A) . Is the area of the triangle bigger than 15 ?

1. A 25

insuffcient
2)
(-1,0)(4,0) (0,A) form right angle

distinace between (-1,0)(4,0) = hypotenuse

$$1^2+A^2+4^2+A^2 = 5^2$$
SOLVE A= +2 OR -2

area <15
suffcient

B

nice explanation x2Suresh

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Re: nice one....   [#permalink] 07 Sep 2008, 01:27
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# Vertices of a triangle have coordinates (-1, 0),(4, 0) ,and

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