W1, W2 are two rectangular tanks. Is lateral surface area of W1 W2?

Question

W1, W2 are two rectangular tanks. Is the  lateral  surface area of W1 greater than that of W2?

(1) Height of tank W1 is equal to that of W2.

(2) W1 has a square base. Area of base of W1 is same as the area of base of W2.

Gladiator59 · Answer

IMO D. W1 and W2 are rectangular tanks so they have a height, width and depth. Essentially they do not have curved surfaces! Hence Curved surface of W1 = 0 = curved surface of W2. Either of Statements are sufficient to answer the prompt. This seems to me the only viable explanation to this question

Please give kudos if you agree with my explanation ...

Jayath · Answer

I think you mean Lateral Surface Area - cuboid and cubes do not have curved surface area. Anyway, are you sure the answer is C?

niks18 · Answer

Hi  Jayath

The answer will be C

The lateral surface area of a cuboid is  2h(l+b)

Statement 1: says height of both the tanks is same, and

Statement 2: says that the base is a square, implying that  l=b

Combining 1 & 2: Hence lateral surface area of either tank will be  2h(l+l)=4hl . Hence both are equal.  Sufficient

amanvermagmat · Answer

Hello

I have edited the question to 'lateral surface area'. Thanks

amanvermagmat · Answer

I think you mean Lateral Surface Area - cuboid and cubes do not have curved surface area. Anyway, are you sure the answer is C?

Hello

I have edited the question to 'lateral surface area'. Thanks

And answer will be C as Niks has explained

cruiseav · Answer

I agree that the answer will be C. But my explanation as below. Plz correct me if i am wong

Lateral surface area of W1; after combining both the statement is 2h(L+L) as it has a square base

So if i assume L=2, then lateral area for W1 becomes = 2h(2+2)

But in statement 2 it is not mentioned that W2 base is also a square; it only says the area of W2 base = base of W1
So, for W2 base, L can be= 1 and B can be=4; so base area of W2 = 4*1 (equal to base area of W1)

Now for W1 lateral area = 2H(2+2) but W2 lateral area = 2H(1+4)

So, W2>W1,(as in statement 1 it is mentioned H is same for both tanks); we can try out different number combinations and always see that W2> W1

The catch here that in statement 2 it is not mentioned that W2 also has a square base (only says it has same base area as W1 )

alax123 · Answer

I think the answer is E because:

Statement 1: h(w1)=h(w2) not sufficient

Statement 2: area of base of w1 = area of base of w2, base of w1 is a square (we do not know if base of w2 is also a square)

Assume area of base of w1=16=area of base of w2
This implies side of base of w1 is 4 but we cannot say for w2, it could be 4 ie square base or 8,2 or 16,1 ie rectangular base, and we do not know the height, therefore not sufficient

Combining both statements,
For w2 base also a square, the LSAs are equal but not if the base of w2 is a rectangle. Therefore E

Correct me if I'm wrong, please share your inputs  Bunuel

W1, W2 are two rectangular tanks. Is lateral surface area of W1 > W2?

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