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Re: W1, W2 are two rectangular tanks. Is lateral surface area of W1 > W2? [#permalink]
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Jayath wrote:
I think you mean Lateral Surface Area - cuboid and cubes do not have curved surface area. Anyway, are you sure the answer is C?


Hi Jayath

The answer will be C

The lateral surface area of a cuboid is \(2h(l+b)\)

Statement 1: says height of both the tanks is same, and

Statement 2: says that the base is a square, implying that \(l=b\)

Combining 1 & 2: Hence lateral surface area of either tank will be \(2h(l+l)=4hl\). Hence both are equal. Sufficient
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Re: W1, W2 are two rectangular tanks. Is lateral surface area of W1 > W2? [#permalink]
Gladiator59 wrote:
amanvermagmat wrote:
W1, W2 are two rectangular tanks. Is the curved surface area of W1 greater than that of W2?

(1) Height of tank W1 is equal to that of W2.

(2) W1 has a square base. Area of base of W1 is same as the area of base of W2.


IMO D.

W1 and W2 are rectangular tanks so they have a height, width and depth. Essentially they do not have curved surfaces!

Hence Curved surface of W1 = 0 = curved surface of W2.

Either of Statements are sufficient to answer the prompt.

This seems to me the only viable explanation to this question :-)

Please give kudos if you agree with my explanation ...


Hello

I have edited the question to 'lateral surface area'. Thanks
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Re: W1, W2 are two rectangular tanks. Is lateral surface area of W1 > W2? [#permalink]
[quote="Jayath"]I think you mean Lateral Surface Area - cuboid and cubes do not have curved surface area. Anyway, are you sure the answer is C?






Hello

I have edited the question to 'lateral surface area'. Thanks

And answer will be C as Niks has explained
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W1, W2 are two rectangular tanks. Is lateral surface area of W1 > W2? [#permalink]
amanvermagmat wrote:
W1, W2 are two rectangular tanks. Is the lateral surface area of W1 greater than that of W2?

(1) Height of tank W1 is equal to that of W2.

(2) W1 has a square base. Area of base of W1 is same as the area of base of W2.

I agree that the answer will be C. But my explanation as below. Plz correct me if i am wong

Lateral surface area of W1; after combining both the statement is 2h(L+L) as it has a square base

So if i assume L=2, then lateral area for W1 becomes = 2h(2+2)

But in statement 2 it is not mentioned that W2 base is also a square; it only says the area of W2 base = base of W1
So, for W2 base, L can be= 1 and B can be=4; so base area of W2 = 4*1 (equal to base area of W1)

Now for W1 lateral area = 2H(2+2) but W2 lateral area = 2H(1+4)

So, W2>W1,(as in statement 1 it is mentioned H is same for both tanks); we can try out different number combinations and always see that W2> W1

The catch here that in statement 2 it is not mentioned that W2 also has a square base (only says it has same base area as W1 )
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Re: W1, W2 are two rectangular tanks. Is lateral surface area of W1 > W2? [#permalink]
I think the answer is E because:

Statement 1: h(w1)=h(w2) not sufficient

Statement 2: area of base of w1 = area of base of w2, base of w1 is a square (we do not know if base of w2 is also a square)

Assume area of base of w1=16=area of base of w2
This implies side of base of w1 is 4 but we cannot say for w2, it could be 4 ie square base or 8,2 or 16,1 ie rectangular base, and we do not know the height, therefore not sufficient

Combining both statements,
For w2 base also a square, the LSAs are equal but not if the base of w2 is a rectangle. Therefore E

Correct me if I'm wrong, please share your inputs Bunuel
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Re: W1, W2 are two rectangular tanks. Is lateral surface area of W1 > W2? [#permalink]
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