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Re: What is the probability of rolling three fair dice and having all thre [#permalink]
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Bunuel wrote:
What is the probability of rolling three fair dice and having all three dice show the same odd number?

A. 71/72
B. 1/36
C. 1/72
D. 1/108
E. 1/216


The probability of the first die’s showing an odd number is 1/2. The probability of the second die’s showing the same number is 1/6. The probability of the third (or last) die’s showing the same number is also 1/6.

Thus, the overall probability is 1/2 x 1/6 x 1/6 = 1/72.

Answer: C
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What is the probability of rolling three fair dice and having all thre [#permalink]
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Bunuel wrote:
What is the probability of rolling three fair dice and having all three dice show the same odd number?

A. 71/72
B. 1/36
C. 1/72
D. 1/108
E. 1/216


Solution



    • We need to get an odd number on each of three dice and all of them must be same.

    • The odd numbers in a dice are 1,3 and 5.

      o Thus, our favourable cases are (1,1,1) (3,3,3) ad (5,5,5)
    • Total cases i.e the the number of ways in which we can get numbers on 3 dice \(= 6 * 6 * 6\)

      o Hence Probability \(= \frac{(Favorable cases)}{(Total Cases)} = \frac{3}{(6*6*6)} = \frac{1}{72}\)
    • Hence, the correct answer is Option C

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Re: What is the probability of rolling three fair dice and having all thre [#permalink]
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We need to find What is the probability of rolling three fair dice and having all three dice show the same odd number?

As we are rolling three dice => Number of cases = \(6^3\) = 216

Out of 1 to 6 there are only three odd numbers 1, 3, 5

Cases in which all three dice will show same odd number will be
(1,1,1), (3,3,3), (5,5,5) => 3 cases

=> P(Three dice will show same odd number) = \(\frac{3}{216}\) = \(\frac{1}{72}\)

So, Answer will be C
Hope it helps!

Watch the following video to learn How to Solve Dice Rolling Probability Problems

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Re: What is the probability of rolling three fair dice and having all thre [#permalink]
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