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Re: What is the value of k if the system of linear equations shown above [#permalink]
IMO A

-2x - ky -9 = 0
4x – 10y + 18 = 0

Multiply first equation with -1 & second equation by \(\frac{1}{2}\)

2x + ky + 9 = 0
2x – 5y + 9 = 0

To have infinite solutions, both equations need to be same i.e. when k = -5 both equations will be identical and will have infinite solutions
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Re: What is the value of k if the system of linear equations shown above [#permalink]
Expert Reply
Bunuel wrote:
-2x - ky -9 = 0
4x – 10y + 18 = 0
What is the value of constant k if the system of linear equations shown above has infinite solutions?

A. -5
B. -1
C. 1
D. 3
E. 5


Solution:

Recall that two linear equations have an infinite number of solutions if and only if one equation is an exact multiple of the other. We see that 4 is -2 times -2 and 18 is -2 times -9. Therefore, -10 has to be also -2 times -k in order to an infinite number of solutions:

-10 = -2(-k)

-10 = 2k

-5 = k

Answer: A
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Re: What is the value of k if the system of linear equations shown above [#permalink]
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Re: What is the value of k if the system of linear equations shown above [#permalink]
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