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When the stock market opened yesterday, the price of a share of stock X was 10 1/2. When the market closed, the price was 11 1/4. Of the following, which is closest to the percent increase in the price of stock X?

A. 0.5%
B. 1.0%
C. 6.7%
D. 7.1%
E. 7.5%

Opening price = \(10.50\)
Closing price = \(11.25\)

Increase in price = \(0.75\)

Percent increase in the price of stock = \(\frac{0.75}{10.50}*100\)

So the answer is (D) 7.14%
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Opening price = 10.50
Closing price = 11.25

Increase in price = 0.75

Formula percent increase= New(11,25)-Old(10,50) / Old(10,50)

Percent increase in the price of stock = 0.75/10.50 ∗ 100

0,75 = 3/4

10,50= 21/2

Substitute 3/4 for 0.75 and 21/2 for 10,50.

3/4 /(divided by) 21/2 becomes 3/4 * 2/21. Simplify it further we get 1/14, which is 7,1 % D
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­Opening price: 10.5
Closing price: 11.25
Price increase: 0.75

Profit % = \(\frac{Price Increase}{Opening Price}\) * 100
= \(\frac{0.75}{10.5}\) * 100

If, you take 10.5 as 10, then the profit % would 7.5%
Since denominator of 10.5 is greater than 10, the profit % must be slightly lesser than 7.5%
Therefore, 7.1% is the answer­
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Hello from the GMAT Club BumpBot!

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