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If we are given that A can do a work in 12 hours and B can do the same work in 18 hours. A started the work and B joined him after 6 hours. How much time will they both take to complete the work?
Let total work = 36 A can do 3 units per hour B can do 2 units per hour
Together they finish 5 units per hour
A started the work and worked alone for 6 hours. Therefore A finished 18 units of work.
Amount of work left= 36-18= 18
I am confused about the steps from here.
What I dis was, I found new units per hour for both A and B
A= 3/2 UNITS/HOUR B= 1 UNIT/HOUR
AND got the answer 36/5 which is incorrect.
What is the error in the above method?
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When we find their efficiency for completing the work, we find it according to the amount of work given. Won't it change when the amount of work will change?
When we find their efficiency for completing the work, we find it according to the amount of work given. Won't it change when the amount of work will change?
When we are given A can complete a work in 12 hours, his efficiency will remain the same no matter how much work is left unless you are told that A is changing his efficiency.
Since A and B have combined efficiency of 5 units/hour, it will remain the same and we will find the time accordingly.
Does that make sense?
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.