Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jul 1508:00 PM PDT
-09:00 PM PDT
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Jul 0901:00 PM EDT
-02:00 PM EDT
More Target Test Prep students are earning 100th percentile GMAT scores. Don’t settle for less when the Target Test Prep course gives you everything you need to score high on the GMAT. Start your 5-day free trial today.- Jul 14
10:00 AM PDT
-11:59 PM PDT
GMAT Preparation Online - A limited time sale use code: EXPERTSGLOBAL10 
Jul 1609:30 AM EDT
-11:30 AM EDT
Is INSEAD your dream b-school and you're looking for solid prep and application strategies to get there? Check out Barkavi’s end-to-end journey to know how she did! Get insights into the INSEAD admissions process, know what Adcoms look at, and more!
Jul 1611:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
Jul 1911:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
74% (01:17) correct
26%
(01:19)
wrong
based on 597
sessions
History
Date
Time
Result
Not Attempted Yet
Working together at their constant rates, pumps X and Y can fill an empty pool to capacity in \(\frac{1}{3}\) hours. How many minutes does it take pump Y, working alone, to fill the pool?
(1) The capacity of the pool is 900 gallons.
(2) The rate of Pump X is 30 gallons per minute.
(1) The capacity of the pool is 900 gallons.
(2) The rate of Pump X is 30 gallons per minute.
Experience a GMAT Club Test Questions
Yes, you've landed on a GMAT Club Tests question
Craving more? Unlock our full suite of GMAT Club Tests here
Want to experience more? Get a taste of our tests with our free trial today
Rise to the challenge with GMAT Club Tests. Happy practicing!
11 Oct 2016, 06:28
Kudos
Bookmarks
Official Solution:
Working together at their constant rates, pumps X and Y can fill an empty pool to capacity in \(\frac{1}{3}\) hours. How many minutes does it take pump Y, working alone, to fill the pool?
To solve the problem, we can use the formula \(rate*time=job\). In the problem, we are given the expression \((x+y)*20=c\), where \(x\) and \(y\) are the flow rates of pumps X and Y, respectively, and \(c\) is the pool's capacity in gallons. The problem asks us to find the value of \(y\).
(1) The capacity of the pool is 900 gallons.
The above gives \(c=900\), which implies that \((x+y)*20 = 900\). As a result, we can deduce that \(x+y=45\). However, this information is not sufficient to get \(y\).
(2) The rate of Pump X is 30 gallons per minute.
Given that \(x=30\), we can then express the equation as \((30+y)*20 = c\). With two unknowns and just one equation, we lack sufficient information. For instance, if \(c = 1000\), then \(y = 20\). However, if \(c = 900\), \(y = 15\).
(1)+(2) From the previous statements, we know that \(x=30\) and \(x+y=45\). By solving these equations, we can determine that \(y=15\) gallons per minute. Therefore, pump Y working alone will take \(\frac{900}{15}=60\) minutes to fill the pool. Sufficient.
Answer: C
Working together at their constant rates, pumps X and Y can fill an empty pool to capacity in \(\frac{1}{3}\) hours. How many minutes does it take pump Y, working alone, to fill the pool?
To solve the problem, we can use the formula \(rate*time=job\). In the problem, we are given the expression \((x+y)*20=c\), where \(x\) and \(y\) are the flow rates of pumps X and Y, respectively, and \(c\) is the pool's capacity in gallons. The problem asks us to find the value of \(y\).
(1) The capacity of the pool is 900 gallons.
The above gives \(c=900\), which implies that \((x+y)*20 = 900\). As a result, we can deduce that \(x+y=45\). However, this information is not sufficient to get \(y\).
(2) The rate of Pump X is 30 gallons per minute.
Given that \(x=30\), we can then express the equation as \((30+y)*20 = c\). With two unknowns and just one equation, we lack sufficient information. For instance, if \(c = 1000\), then \(y = 20\). However, if \(c = 900\), \(y = 15\).
(1)+(2) From the previous statements, we know that \(x=30\) and \(x+y=45\). By solving these equations, we can determine that \(y=15\) gallons per minute. Therefore, pump Y working alone will take \(\frac{900}{15}=60\) minutes to fill the pool. Sufficient.
Answer: C
General Discussion
26 Dec 2023, 08:30
Kudos
Bookmarks
javzprobz
Working together at their constant rates, pumps X and Y can fill an empty pool to capacity in 1/3 hours. How many minutes does it take pump Y, working alone, to fill the pool?
(1) The capacity of the pool is 900 gallons.
(2) The rate of Pump X is 30 gallons per minute.
(1) The capacity of the pool is 900 gallons.
(2) The rate of Pump X is 30 gallons per minute.
Let's see the information we have with respect to the quantities we know: Rate, Time, Work
Time taken together = 1/3 hr = 20 mins (I will prefer to work with 20 mins here because the question is asking the time in minutes and the statement 2 provides rate is mins)
We need the time taken by Y alone.
(1) The capacity of the pool is 900 gallons.
This is the capacity of the pool i.e. the work that has to be done. I can say that work done = 1 pool or I can say that work done = 900 gallons. They both represent the same thing in different units.
Now I know the work that has to be done in different units i.e. 900 gallons. From the question stem, I knew that the work to be done is 1 pool.
This means that their rate together was either 1/(1/3) = 3 pools/hr
or it can be written as 900/20 = 45 gallons/min
They both represent the same rate (of both pumps working together)
I don't know the rate of pump X so I cannot find the rate of pump Y. Not sufficient alone.
(2) The rate of Pump X is 30 gallons per minute.
Rate of pump X = 30 gallons/min but I still don't know the rate of pump Y because these units are different from the units of pool/hr that the question gives us. Since I don't know the equivalency of pool and gallons, I cannot convert one rate to another.
I don't know the combined rate in terms of gallons/min so I cannot find the rate of pump Y. Not sufficient alone.
Using both statements together,
We know that combined rate is 45 gallons/min i.e. both pumps together are putting in 45 gallons of water in one min. But pump X is putting in 30 gallons every min. So pump Y must be putting in the other 15 gallons per min.
Rate of pump Y = 15 gallons/min.
Then if I had to find the time taken by pump Y alone, I simply do
Time = work/rate = 900 gallons/15 gallons per min = 60 mins
